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3 years ago

Can anyone help me plz and I need the person to explain it for me

Mathematics

2 answers:

lions [1.4K]3 years ago

6 0

Answer:

1 cm = 100 mi

28.9/1=28.9

28.9 x 100 = 2890 miles distance

2890 / 65 miles per hour = 44.4615 hours to drive

44.461/24 hours in a day = 1.85 rounded up is 2 days

About two days

If you have any questions you can ask

Step-by-step explanation:

MatroZZZ [7]3 years ago

5 0

Answer:

a) 2900

b) about 44 hours

2 days

Step-by-step explanation:

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I dont understand what the question is asking me

kipiarov [429]

Answer:

$\huge\boxed{\sf$

Step-by-step explanation:

∠E = 1/2 (mCD - mAB)

<u>Where mCD = 110° and mAB = 30°</u>

∠E = 1/2 (110° - 30°)

∠E = 1/2 (80°)

∠E = 40°

$\rule[225]{225}{2}$

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3 years ago

Solve the inequality (x + 4)(x - 1) < 0.

Rzqust [24]

Answer: −4<x<1

Step-by-step explanation: plz mark brainliest

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4 years ago

A( 3tx – 2b) = c(dx - 2)

olganol [36]

Answer:

A3tx-A2b=cdx-2c

Step-by-step explanation:

Distribution

8 0

3 years ago

A discount store takes 50% off of the retail price of a desk. For the store's holiday sale, it takes an additional 20% off of al

Serhud [2]

We are given the retail price of desk as $320. The store takes 50% off of the retail price of desk, then its price would become half of the original.

So its new price would be $160.

Now it says that it takes an additional 20% off of all furniture on store's holiday sale. So we need to cut off 20% from new price $160.

Holiday discount = 20% of $160 = 0.2 × 160 = 32.

Final selling price would be = $160 - $32 = $128.

So $128 is the final answer.

3 0

3 years ago

Read 2 more answers

Suppose that the weights of 5400 registered female Labrador retrievers in the United States are distributed normally with a mean

Maurinko [17]

Answer:

$N= 4543$ Labrador retrievers

Step-by-step explanation:

We know that the mean $\mu$ is:

$\mu = 62.5$

and the standard deviation $\sigma$ is:

$\sigma=2.5$

The probability that a randomly selected Labrador retriever weighs less than 65 pounds is:

$P(X$

We calculate the Z-score for X =65

$Z = \frac{X-\mu}{\sigma}\\\\Z =\frac{65-62.5}{65}=1$

$P(X$

Looking in the table for the standard normal distribution we have to:

$P(Z$ .

Finally the amount N of Labrador retrievers that weigh less than 65 pounds is:

$N = P(X$

$N = 0.8413*5400$

$N= 4543$ Labrador retrievers

6 0

3 years ago