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natka813 [3]
3 years ago
10

Slips of paper are numbered 1 through 10. If one slip is drawn and replaced 40 times, how many times should the slip with number

10 appear?
Mathematics
1 answer:
Masja [62]3 years ago
6 0

Hey there!

We have 10 pieces of paper. The probability of drawing a 10 is 1/10.  Therefore, if we were to draw ten times, the ten should probably be drawn once. If we multiplied our number of drawings by four (10*4=40), our outcome of seeing our slip with the ten should also quadruple and become four times. (1*4=4)

I hope that this helps! Have an awesome day!

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A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gi
inessss [21]

Answer:

\frac{1429}{120} or 11\frac{109}{120}

Step-by-step explanation:

Given:

A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gives 7 peaches to a 5th person.

Remaining peaches = 4

We need to find the original number of peaches in the basket.

The farmer gives the total number of peaches = \frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7

Let x be the former gives the total number of peaches

We multiply and divide by 120 in right side of the above equation because of 120 is divided by all given denominator and then simplify.

x = \frac{120}{120}(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7)

x = \frac{1}{120}(\frac{120}{3}+\frac{120}{4}+\frac{120}{5}+\frac{120}{8}+7\times 120)

x = \frac{1}{120}(40+30+24+15+840)

x = \frac{1}{120}(949)

x = \frac{949}{120}

We add the remaining peaches by given peaches for the original number of peaches in the basket.

Original number of peaches = \frac{949}{120}+4

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Therefore the original number of peaches in the basket is \frac{1429}{120} or 11\frac{109}{120}

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