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svetoff [14.1K]
3 years ago
13

Check

Mathematics
1 answer:
Tanzania [10]3 years ago
3 0

Answer: first, second and fourth are primes, the third is not-prime.

Step-by-step explanation:

A prime polynomial can not be reduced.

Let's see the options:

A) 6x^3 - 5x^2 + 2^x-14

You can see that we have a coefficient equal to 5 and other equal to 2.

As both are prime numbers, we can not reduce this, so this is a prime polynomial.

B) 12x^4 - 18x^2 + 8x^2 - 12 = 12x^4 -10*x^2 + 124

Both coefficients are even, so we can reduce it to:

12x4 -10*x^2 + 124 = 2*(6x^4 -5*x^2 + 72)

So this is not prime.

C) 6x^3 + 9x^2 + 10x + 15

we have that:

6 = 3*2

9 = 3*3

10 = 2*5

15 = 3*5

a polinomial is only reducible if all the coefficients share at least one prime factor, here we can see that this is not the case, so this is a prime polinomial.

D) 12x^2 -3x + 4x + 7 = 12x^2 + x + 7

Again, here we have that one coefficient is 1, the only factor of 1 is itself, so we can not reduce this polinomial, this is prime.

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gogolik [260]

Answer:

Option B.

Step-by-step explanation:

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If the slope of the line is same as the slope of y axis then the line passing through these points will be parallel to the y axis.

Slope of y - axis = ∞

Option A). Slope = \frac{y-y'}{x-x'}

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Therefore, line passing through points (3.2, 8.5) and (3.22, 24) is not parallel to y axis.

Option B). Slope of the line passing through (\frac{40}{3},\frac{14}{3}) and (\frac{40}{3},7) will be

= \frac{\frac{14}{3}-7}{\frac{40}{3}-\frac{40}{3}}

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Option C). Slope of the line passing through (2.9,5.4) and (7.2, 5.4)

= \frac{5.4-5.4}{7.2-2.9}

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Option B. is the answer.

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3 years ago
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LCM of 12 and 17 = 204

Hope this helps!

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3 years ago
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Answer:

See below.

Step-by-step explanation:

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