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german
3 years ago
14

I can't figure this question out can I please have help with this question​.

Mathematics
1 answer:
Alex787 [66]3 years ago
3 0

Step-by-step explanation:

The picture is in sphere shape

so if you move it will be in the same position

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Imagine that yourfriend missed the lesson on how to solve a system of equations using the substitution method. You want to help
Lana71 [14]
A system of equations is a collection of two or more equations with the same variables. When solving this system, u need to find the unknown variables. One way of solving a system of equations is by substitution. 

example :

2x + 2y = 6 (equation 1)
3x + y = 4 (equation 2)

we need to pick a variable and isolate it. The easiest one to pick since it is already by itself is the y in the second equation.
3x + y = 4.....subtract 3x from both sides
y = -3x + 4

now we can sub -3x + 4 in for y in the 1st equation...u have to make sure u sub it back into the 1st equation and not the same equation u used to find it.

2x + 2y = 6.....sub in -3x + 4 in for y and solve for x
2x + 2(-3x + 4) = 6...distribute thru the parenthesis
2x - 6x + 8 = 6...subtract 12 from both sides
2x - 6x = 6 - 8...simplify
-4x = -2...divide both sides by -4
x = -2/-4
x = 1/2

now that we have a numerical number for x, u can sub this back into either of ur equations to find a numerical answer for y.

y = -3x + 4...when x = 1/2
y = -3(1/2) + 4
y = -3/2 + 4
y = -3/2 + 8/2
y = 5/2

so ur solution is : (1/2,5/2) <===

and u can check ur answers by subbing them into ur equations to see if they satisfy both equations...because for it to be a solution to this system, it has to satisfy both equations and not just one of them
5 0
3 years ago
The age of United States Presidents on the day of their first inauguration follows a Normal distribution with mean 56 and standa
Talja [164]

Answer:

a) 0.7088 = 70.88% probability that a randomly selected President was less than 60 years old on the day of their first inauguration.

b) The 75th percentile for the age of United States Presidents on the day of inauguration is 61.

c) 0.8643 = 86.43% probability that the average age on the day of their first inauguration for a random sample of 4 United States Presidents exceeds 60 years.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The age of United States Presidents on the day of their first inauguration follows a Normal distribution with mean 56 and standard deviation 7.3.

This means that \mu = 56, \sigma = 7.3

(a) (5 points) Compute the probability that a randomly selected President was less than 60 years old on the day of their first inauguration.

This is the pvalue of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 56}{7.3}

Z = 0.55

Z = 0.55 has a pvalue of 0.7088

0.7088 = 70.88% probability that a randomly selected President was less than 60 years old on the day of their first inauguration.

(b) (5 points) Compute the 75th percentile for the age of United States Presidents on the day of inauguration.

This is X when Z has a pvalue of 0.75. So X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 56}{7.3}

X - 56 = 0.675*7.3

X = 61

The 75th percentile for the age of United States Presidents on the day of inauguration is 61.

(c) (5 points) Compute the probability that the average age on the day of their first inauguration for a random sample of 4 United States Presidents exceeds 60 years.

Now, by the Central Limit Theorem, we have that n = 4, s = \frac{7.3}{\sqrt{4}} = 3.65

This is the pvalue of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{60 - 56}{3.65}

Z = 1.1

Z = 1.1 has a pvalue of 0.8643

0.8643 = 86.43% probability that the average age on the day of their first inauguration for a random sample of 4 United States Presidents exceeds 60 years.

4 0
3 years ago
Simplest form 816/10
Anna35 [415]
It’s 408/5 in the simplest form. To find the answer just divide the numbers.
6 0
3 years ago
I'm stuck in this question and need some help for this. Thank you
marishachu [46]
I am positive it is B
6 0
3 years ago
Read 2 more answers
How to work with this? If multiple it 12*4=48 which is not correctly.
Katyanochek1 [597]

Answer:

Step-by-step explanation:

You must have not input your units of cm^2

5 0
3 years ago
Read 2 more answers
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