Answer:
i'm pretty sure it's c
Step-by-step explanation:
<h3>Answer:</h3>
33
<h3>Explanation:</h3>
The repeating digits of the sum will have a cycle of length 6 (the LCM of 2 and 3). There will be 3 cycles of the 2-digit repeat, and 2 cycles of the 3-digit repeat.
The sum of digits of the cycle of interest is the sum of the digits in 3 cycles of "12" and 2 cycles of "345", thus 3·(1+2) +2(3+4+5) = 9+24 = 33.
![0.\overline{12}+0.\overline{345}=0.\overline{121212}+0.\overline{345345}\\\\=0.\overline{466557}\\\\4+6+6+5+5+7=33](https://tex.z-dn.net/?f=0.%5Coverline%7B12%7D%2B0.%5Coverline%7B345%7D%3D0.%5Coverline%7B121212%7D%2B0.%5Coverline%7B345345%7D%5C%5C%5C%5C%3D0.%5Coverline%7B466557%7D%5C%5C%5C%5C4%2B6%2B6%2B5%2B5%2B7%3D33)
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<em>Another approach</em>
You can look at the sum on a per-digit basis. The 2-digit repeat {12} has a sum of 1+2=3, or 3/2 on a per-digit basis. The 3-digit repeat {345} has a sum of 12, or 12/3=4 on a per-digit basis. The sum of the two repeating decimals will have a sum per digit of 3/2 + 4 = 5 1/2. The 6 repeating digits will then have a sum of 6×(5 1/2) = 33.
Answer:
I am pretty sure the answer is B, 22
Step-by-step explanation
Answer:
y = (√x)/13 for x > 0
Step-by-step explanation:
Actually, this is f(x) = 169x^2; the " ^ " indicates exponentiation. The graph consists of the right-hand half of the parabola 169x^2. Before we attempt to find the inverse function, we determine whether or not this function passes the vertical line test. If x is restricted to (0, infinity), a horizontal line intersects this graph only once. Therefore, this function has an inverse.
1. Replace 'f(x)' with 'y:' y = 169x^2
2. Interchange x and y: x = 169y^2
3. Solve for y: y^2 = x/169, or y = (√x)/13 for x > 0
Answer:
I'm Pretty sure The answer Is D) She will earn more in Company 2.
Step-by-step explanation:
Please correct Me If i'm wrong! Thanks