<span>2(3)× = 3×+1 is equal when f(x) = g(x).
f(x) is equal to g(x) when x = 0.
Therefore, the solution to the equation </span><span>2(3)×=3×+1 is x = 0.</span>
Answer:
see below
Step-by-step explanation:
7. f(x) = mx + b; b acts as the vertical shift moving the graph up if b is positive and down if b is negative.
f(x) = x-2 has shifted the graph of f(x) down 2 units.
g(x) = x + 7 has shifted the graph up 7 units.
If f(x) is changed to g(x) the vertical shift has gone from -2 to + 7 or (7-(-2) = 9 units up
8. f(x) = mx stretches the graph by a factor of m if m > 0 and compresses the graph by a factor of m if 0<m<1
f(x) = 3x stretches the graph by a factor of 3.
g(x) = 1/4x compresses the graph by a factor of 1/4
Answer:
cos P = 53 degrees
cos Q = 37 degrees
Step-by-step explanation:
cos P = 
cos P = 
cos P = 0.60
Cos-1 of 0.60 is 53.13 (round to the nearest whole number)
cos P = 53 degrees
cos Q = 
cos Q = 
cos Q = 0.80
Cos of 0.80 is 36.86 (round to the nearest whole number)
cos Q = 37 degrees
To check anser:
90 + 53 + 37 = 180
180 = 180
<h3>What is the greatest common factor of 15x³y² and 20x⁴y⁴? </h3>
<em>First we have to find the factors of 15x³y²</em>
<em>15x³y² = 3 * 5x³y² </em>
<em>Then we have to find the factors of 20x⁴y⁴</em>
<em>20x⁴y⁴ = 2²x¹y² * 5x³y²</em>
<em>Now we have to find the common factors to both numbers.</em>
<em>The common factors are </em><em>5x³y²</em>
Answer : GCF = (15x³y²,20x⁴y⁴) = 5x³y²
Hope this helps!



→ Substitute cos 2x and sin 2x by their expressions

→ Subtract both sides by sin x

→ Take sin x as a common factor in the right side

From the graph, the equation has 4 solutions, the intersection points between the 2 graphs