96 / 150 = 0.64.
.64 x 100 = 64%
If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
Learn more about half life here
brainly.com/question/4318844
#SPJ4
X+6=11
X-11=-6
5x=25
2x=10
2x+15=25
Answer:
27π cm²
Step-by-step explanation:
step 1
Find the area of the complete circle
The area of the circle is equal to
A=πr²
we have
r=9 cm
substitute
A=π(9)²=81π cm²
step 2
Remember that the area of complete circle subtends a central angle of 360°
so
using proportion
Find the area of a sector formed by a central angle that measures 120°
81π/360°=x/120°
x=120°*81π/360°
x=27π cm²
Volume is l × w × h
l = 21 in
h = 5 in
w = ?
volume = 1575 in
21 × 5 × w = 1575
105 × w = 1575
w = 1575 ÷ 105
w = 15 inches