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Morgarella [4.7K]
3 years ago
13

I don't know how to solve this

Mathematics
1 answer:
sergiy2304 [10]3 years ago
4 0
The answer that I got was side  WX = 12 inches

It says that WY is congruent to XY which means that they are the same. That means that XY is also 3m-4. It also says that the perimeter of the triangle is 76 inches.

With this information I set up an equation:

3m-4 + 3m-4 +m = 76

(The number on the right side is the perimeter given to us in the problem and the numbers on the left side are the 3 side lengths).

I combined like terms on the left side and ended up with:

7m-8=76 

I added 8 to both sides of the equation and got 7m=84.

Finally I divided both sides by 7 and got m=12

m is equivalent to side WX..

Hope this helps!
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egoroff_w [7]
Cuberoot(10)^4 is the answer
3 0
3 years ago
Factor 3a^3 + 18a² + 8a + 48 completely.
fomenos

Answer:

(3a2 + 8) • (a - 6)

Step-by-step explanation:

STEP 1:

Equation at the end of step 1

 (((3 • (a3)) -  (2•32a2)) +  8a) -  48

STEP  2:

Equation at the end of step 2:

 ((3a3 -  (2•32a2)) +  8a) -  48

STEP 3:

Checking for a perfect cube

3.1    3a3-18a2+8a-48  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  3a3-18a2+8a-48

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  8a-48

Group 2:  -18a2+3a3

Pull out from each group separately :

Group 1:   (a-6) • (8)

Group 2:   (a-6) • (3a2)

              -------------------

Add up the two groups :

              (a-6)  •  (3a2+8)

Which is the desired factorization

Polynomial Roots Calculator :

3.3    Find roots (zeroes) of :       F(a) = 3a2+8

Polynomial Roots Calculator is a set of methods aimed at finding values of  a  for which   F(a)=0  

It would only find Rational Roots that is numbers  a  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  3  and the Trailing Constant is  8.

The factor(s) are:

of the Leading Coefficient :  1,3

of the Trailing Constant :  1 ,2 ,4 ,8

3 0
3 years ago
What is next in the sequence? -1,2,7,14,23​
BabaBlast [244]

Answer:

11

Step-by-step explanation:

yes

5 0
3 years ago
Find the value of unknown figure plz tell i will mark as brainliest
NeTakaya

Answer:

1. 2^{3} x 3^{6}

ii. 18

b. -12

2. nth = a + (n - 1)d

ii. k = 103

3. x^{o} = 27^{o}

4. Volume = 25.025 m^{3}

Step-by-step explanation:

1. Prime factors of 5832 = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 3

                                       = 2^{3} x 3^{6}

ii. \sqrt[3]{5832} = 18

b. 2a^{2} - 3b^{2} + 3abc

a = 3, b = 2, c = -1

Thus,

2(3)^{2} - 3(2)^{2} + 3(3 x 2 x -1)

= 18 - 12 - 18

= -12

2. The required formula is;

nth = a + (n - 1)d

where: a is the first term, n is the number of terms in the sequence and d is the common difference.

b. kth term = 304, then

304 = -2 + (k - 1) 3

      = -2 + 3k -3

      = 3k - 5

3k = 304 + 5

3k =  309

k = \frac{309}{3}

  = 103

k = 103

3. Comparing <DAB and < EBC;

<DAB ≅ <EBC = x^{o}

<BEC = 90^{o} (right angle property)

<C = 63^{o}

Thus,

<B + <C + <E = 180^{o} (sum of angles in a triangle)

x^{o} + 63^{o} + 90^{o} = 180^{o}

x^{o} + 153 = 180^{o}

x^{o} = 180 - 153

   = 27

x^{o} = 27^{o}

4. Volume of a cylinder = \pir^{2}h

where r is the radius and h is the height of the cylinder.

Diameter = 3.5 m, h = 2.6 m

r = \frac{3.5}{2}

r = \frac{7}{4} m

So that,

Volume = \frac{22}{7} x (\frac{7}{4}) ^{2} x 2.6

             = \frac{22}{7} x \frac{49}{16} x \frac{13}{5}

             = 25\frac{1}{40}

Volume = 25.025 m^{3}

6 0
3 years ago
Which expression is equivalent to
pickupchik [31]

✿————✦————✿————✦————✿

This is the answer:

✿————✦————✿————✦————✿

Step:

* To raise a power to another power, multiply the exponents. Multiply 1/2 and −2 to get −1.

* To raise a power to another power, multiply the exponents. Multiply −1/4  and −2 to get  1/2.

4 0
2 years ago
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