Let's try to find some primes that divide this number.
The number is not divisible by 2, because it is odd.
The number is divisible by 3 though, because the sum of its digits is:
![6+5+1+6+9=27=3\cdot 9](https://tex.z-dn.net/?f=6%2B5%2B1%2B6%2B9%3D27%3D3%5Ccdot%209)
So, we can divide the number by 3 and keep going with the factorization:
![65169\div 3 = 21723](https://tex.z-dn.net/?f=%2065169%5Cdiv%203%20%3D%2021723%20)
This number is again divisible by 3, because
![2+1+7+2+3 = 15 = 3\cdot 5](https://tex.z-dn.net/?f=%202%2B1%2B7%2B2%2B3%20%3D%2015%20%3D%203%5Ccdot%205%20)
We have
![21723\div 3 = 7241](https://tex.z-dn.net/?f=%2021723%5Cdiv%203%20%3D%207241%20)
This number is no longer divisible by 3. Let's go on looking for primes that divide it: 5 doesn't because the number doesn't end in 0 nor 5. This number is not divisible by 7 or 11 either (just try). It is divisible by 13 though: we have
![7241\div 13 = 557](https://tex.z-dn.net/?f=%207241%5Cdiv%2013%20%3D%20557%20)
And 557 is prime, so we're done. This means that the prime factorization of 65169 is
![3^2\cdot 13 \cdot 557](https://tex.z-dn.net/?f=%203%5E2%5Ccdot%2013%20%5Ccdot%20557%20)