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Over [174]
2 years ago
14

H(n)=63(-1/3)^n Complete the recursive formula of h(n)

Mathematics
1 answer:
taurus [48]2 years ago
3 0

Answer:

h(n+1) = -⅓ h(n), h(0) = 63

Step-by-step explanation:

h(n) = 63 (-⅓)ⁿ

This is a geometric series where the first term is 63 and the common ratio is -⅓.

Therefore, each term is -⅓ of the previous term.

h(n+1) = -⅓ h(n), h(0) = 63.

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zheka24 [161]
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1║2  -7  -13    63  -45
  ║     2    -5  -18    45
    2  -5  -18    45    0
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Use synthetic division on the decomposed polynomial to find the next zero.
I chose x = 3 (which represents the factor "x-3")

3║2  -5  -18    45 
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    2   1  -15     0   

Using synthetic division, we discovered that (x-1), (x-3), & (2x² + x -15) are factors.  Take the new decomposed polynomial (2x² + x -15) and find the last two factors using any method.

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