Answer:
Cost of a coffee is <u>$2.5</u> and cost of a latte is <u>$4.25.</u>
Step-by-step explanation:
Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.
Given:
4 coffees and 12 lattes cost $61.
12 coffees and 7 lattes cost $59.75.
∵ 1 coffee cost = 
∴ 4 coffees cost =
and 12 coffee cost = 
∵ 1 latte cost = 
∴ 12 lattes cost =
and 7 lattes cost = 
Now, as per question:

Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,

Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,

Therefore, cost of a coffee is $2.5 and cost of a latte is $4.25.
9(2k+3)+2=11 (k-y)
k=-11/7 y+ -29/7
No, he needs to do 5(to the power of 2) plus 3(to the power of 2)
this should give him 25 plus 9 = 34
You add all those number together then divide the number you got by how many numbers there are and that's your answer, 61.1
edit : dont listen to me I didnt see the numbers 64 and 65, im sorry