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BigorU [14]
3 years ago
15

Like what is the square root of 35 like what is it a real number? irrational and like that

Mathematics
1 answer:
Maslowich3 years ago
4 0

Answer:

can you give us the question copy and paste bc like that makes it harder to understand

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Factor completely, x^2+25.<br><br> A).(X+5)(X+5).<br> B).(X+5)(X-5).<br> C).(X-5)(X-5).<br> D.Prime.
Tatiana [17]
The answer you are looking for is B. If you use the FOIL method (first,outer,inner,last) of multiplication, you will find that (x+5) times (x-5) is actually x^2+25. Hope this helps! Comment if you have questions!!! :)
4 0
3 years ago
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Solve for b. C=b225 b=±5C√C b=±C√5 b=±5C b=±5C‾‾√
Pachacha [2.7K]
B=±5<span>√<span>​<span>c

Now if you ever need help a website you can use is cymath, i use it for my school and its how i found out your answer here, it has never been wrong for me, i'm just a student myself. Good Luck!
</span></span></span>

Please give me brainiest! I’m striving for the next rank!

6 0
3 years ago
Please Help ASAP!!!!!!!!
aleksandr82 [10.1K]
Your slope=-2
Which is 2/1 (rise/run)
Your y-int=-1 (which means your graph should touch the -1 on the y-int

So your answer would be A
4 0
3 years ago
PLEASE HELP! Image below
maria [59]

Answer:

1.6

Step-by-step explanation:

So, first, write down the number of jokers in each deck of cards.

That would be: 0, 1, 2, 2, 3

Then, add up all those numbers.

0+1+2+2+3=8

Now, divide that sum by the number of decks or cards shown in the data set, which would be 5.

8/5=1.6

So, the mean of the data in the dot plot shown is 1.6.

:L)

4 0
3 years ago
What is the horizontal asymptote of the rational function f(x) = 3x / (2x - 1)?
-BARSIC- [3]

Answer:

Step-by-step explain

Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :

A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)

If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.

For the given function, there is no horizontal asymptote.

We can find the slant asymptote by using long division:

(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))

The slant asymptote is y=3/2x+3/4

6 0
3 years ago
Read 2 more answers
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