$AB=\sqrt{(-11-(-7))^{2}+(4-8)^{2}}=\sqrt{16+16}=4\sqrt{2}\\AC=\sqrt{(-11-(-4))^{2}+(4-4)^{2}}=7\\BC=\sqrt{(-7-(-5))^{2}+(8-4)^{2}}=\sqrt{4+16}=2\sqrt{5}\\\\$

So the perimeter is $4\sqrt{2}+7+2\sqrt{5}$

3 0

2 years ago

List these numbers from least to greatest. -10, 20, -30, 15

allochka39001 [22]

Answer: -30, -10, 15, 20

Step-by-step explanation:

4 0

3 years ago

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Consider a point, N, located at (6, 8). Name the

Fofino [41]

Answer: (6,16)
(6,2)
(-2,8)
(14,8)

5 0

3 years ago

Which of these transformations appear to be a rigid motion? <br> Please help me!!!!!

Alenkasestr [34]

The answer is the third answer choice, I and II only.

This is because both of those motions are rigid since they are just reflections and III is not a rigid motion since it is a dilation, the second triangle is bigger than the first.

Hope this helps!

7 0

3 years ago

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