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jolli1 [7]
2 years ago
12

0.10 x 37.7 explain please

Mathematics
1 answer:
kodGreya [7K]2 years ago
5 0

Answer: The answer is 3.77.

Explanation: Since 0.10 is 10 times smaller than 1, we know that if we divide 37.7 by 10, we will get the same answer as 0.10 x 37.7.

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What do I do I’m lost I need help?
ale4655 [162]

Answer:

27

Step-by-step explanation:

the sequence is 4 added to each number. 4 added to 23 is 27

8 0
2 years ago
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in a program designed to help patients stop smoking 232 patients were given sustained care and 84.9% of them were no longer smok
grandymaker [24]

Answer:

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

Step-by-step explanation:

1) Data given and notation

n=232 represent the random sample taken

X represent the adults were no longer smoking after one month

\hat p=0.849 estimated proportion of adults were no longer smoking after one month

p_o=0.80 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.8.:  

Null hypothesis:p=0.8  

Alternative hypothesis:p \neq 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

6 0
3 years ago
In the context of relationship between variables, increases in the values of one variable are accompanied by increases in the va
garik1379 [7]

Answer:

A. Positive linear.

Step-by-step explanation:

We have that both variables increases, then we have a positive relation. A curvilinear option can not be possible because with this option in some regions could happen that when one variable increases the other one decreases. The negative linear relation can no be because with this option when one variable increases the other decreases. A non linear option is the same as a curvilinear option then can not be possible. Then the best option is a positive linear relationship.

7 0
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Explain what makes 3.23 a decimal number.
nignag [31]

Answer:

the point

Step-by-step explanation:

the point makes a decimal a decimal

7 0
3 years ago
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If y=6 what is 4Y-5?
dybincka [34]

Answer:

41 if I'm reading the question right.

3 0
3 years ago
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