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Art [367]
2 years ago
5

Katy bought 5 packages of cake mix for $32.50. How much would 8 packages of cake mix cost?

Mathematics
1 answer:
AleksAgata [21]2 years ago
7 0

Answer:

$52

Step-by-step explanation:

5 packages = $32.50

divide both sides by 5

1 package = $6.50

times by 8

8 package = $52

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The perimeter of the rectangle below is 96 units. Find the length of side RS.
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96÷3=32z

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Solve each system using SUBSTITUTION. Remember to check!
Annette [7]

Answer:

\left \{ {{x=3} \atop {y=-7}} \right.

Step-by-step explanation:

We can directly substitute y of the first equation to the second equation.

-2x - 1 = 3x - 16

5x = 15

x = 3

Substituting back to any of the two equations, we get y = -2(3)-1 = -7.  If you check with the second equation, y = 3(3)-16 = -7 as well.

Therefore \left \{ {{x=3} \atop {y=-7}} \right..

7 0
2 years ago
National data indicates that​ 35% of households own a desktop computer. In a random sample of 570​ households, 40% owned a deskt
Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a​ desktop.

Step-by-step explanation:

We are given that National data indicates that​ 35% of households own a desktop computer.

In a random sample of 570​ households, 40% owned a desktop computer.

<em><u>Let p = population proportion of households who own a desktop computer</u></em>

SO, Null Hypothesis, H_0 : p = 25%   {means that 35% of households own a desktop computer}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 570​ households who owned a desktop computer = 40%

            n = sample of households = 570

So, <u><em>test statistics</em></u>  =  \frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }

                               =  2.437

<em>Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</em>

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0
3 years ago
Nina bought 3.45 pounds of walnuts and 1.83 pounds of almonds. How many more pounds of walnuts did she buy than almonds
tia_tia [17]

Answer:

subtract them

Step-by-step explanation:

8 0
2 years ago
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