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harina [27]
4 years ago
12

Help a girl out please

Mathematics
2 answers:
Furkat [3]4 years ago
8 0
You need to find the scale by taking the same side of each polygon. I marked which sides you should take from each example.

Scale factor is defined as the proportion of the one side to another. In our case: smaller side/ bigger side

1) scale factor k=9/12=3/4, which means that smaller figure is a 1/4 fourth smaller than the bigger one

2) k = 12/15= 4/5, which means that smaller figure is one fifth smaller than the bigger one

3) k =10/25= 2/5, so the bigger figure is 3/5 smaller from the bigger one

4) k= 8/16, which means that the smaller figure is a half of the bigger one
sergiy2304 [10]4 years ago
7 0

Answer: 1. I forgot how you write it but it adds 1/3 of the number, so for example 9/3 is 3, so you add 3 to 9 = 12 and then 21/3 is 7 and so you add 7 to 21 = 28. I forgot how you would write this but I know the answer is not 1/3 though because then that would be dilating. (srry this one isn't clear)

Also sorry I couldn't really help more I'm not very good at this stuff.

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Step-by-step explanation:

4g + 2 ≥ - 14

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ValentinkaMS [17]

Answer:

Richard used 2\frac{1}{12}\ yd ^2 of fabric for his project.

Step-by-step explanation:

Given:

Total amount of fabric = 11\frac23\ yd^2

Now To convert a mixed fraction to an improper fraction, Multiply the whole number part by the fraction's denominator,  Add that to the numerator,Then write the result on top of the denominator.

11\frac23\ yd^2 can be Rewritten as \frac{35}{3}\ yd^2

Number of pieces fabric was cut = 4

Richard is given one of four pieces of equal-sized fabric.

Amount of fabric Richard was given = \frac14 \times \frac{35}{3}=\frac{35}{12}\ yd^2

Amount of fabric left with Richard = \frac56 \ yd^2

We need to find the amount of fabric Richards used for his project.

Solution:

Now we can say that;

amount of fabric Richards used for his project is equal to Amount of fabric Richard was given minus Amount of fabric left with Richard.

framing in equation form we get;

amount of fabric Richards used for his project = \frac{35}{12}-\frac56

Now we will make the denominator common using LCM we get;

amount of fabric Richards used for his project = \frac{35}{12}-\frac{5\times2}{6\times2} = \frac{35}{12}-\frac{10}{12}

Now Denominator is same so we will solve the numerator.

amount of fabric Richards used for his project  = \frac{35-10}{12}= \frac{25}{12}\ yds^2

\frac{25}{12}\ yds^2 can be rewritten as 2\frac{1}{12}\ yd ^2

Hence Richard used 2\frac{1}{12}\ yd ^2 of fabric for his project.

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