Jace made 3 three pointers and 6 free throws.
3(3) + 6(1) = 15
Free throws = f
Three pointers = t
t(2) = f
t + f = 15
Answer:
aₙ = -15 + 10 * (n-1)
Step-by-step explanation:
aₙ = a₁ + (n-1)*d a₁: first term d: common difference
a₅ a₁ + 4d =25 .... (1)
a₁₁ a₁ + 10d = 85 ...(2)
(2) - (1) 6d = 60
d = 10
a₁ = -15
Formula: aₙ = -15 + 10 * (n-1)
Answer:
Stefanie bought 10 erasers
Step-by-step explanation:
We can establish the following equation:
TP = NP*PP + NE*EP
Where:
TP = Total price; (4.25)
NP = Number of pencil packages; (1)
PP = Pencil Package's Price; (1.75)
NE = Number of erasers; (What we are looking for)
EP = Erasers Price; (0.25);
Then:
4.25 = 1*1.75 + NE*0.25;
4.25 - 1.75 = NE*0.25;
2.5/0.25 = NE;
10 = NE.
X=1/2-3y/4
and
x=10/3+2y/3
