1. In the number 123,546,870, which digit is in the hundred thousands place?
1 answer:
You might be interested in
Answer:
the value of x and y is 4 and (-1) respectively
Hope this helps. Good luck
Step-by-step explanation:
A, B and C are integers between 1 and 10 such that A<B<C.
The value of A can be minimum 1 and maximum 8.
If A = 1, B = 2, then C can be one of 3, 4, 5, 6, 7, 8, 9, 10 (8 options).
If A = 1, B = 3, then C has 7 options (4, 5, 6, 7, 8, 9, 10).
If A = 1, B = 4, then C has 6 options (5, 6, 7, 8, 9, 10).
If A = 1, B = 5, then C has 5 options (6, 7, 8, 10).
If A = 1, B = 6, then C has 4 options (7, 8, 9, 10).
If A = 1, B = 7, then C has 3 options (8, 9, 10).
If A = 1, B = 8, then C has 2 options (9, 10).
If A = 1, B = 9, then C has 1 option (10).
So, if A = 1, then the number of combinations is
Similarly, if A = 2, then the number of combinations is
If A = 3, then the number of combinations is
If A = 4, then the number of combinations is
If A = 5, then the number of combinations is
If A = 6, then the number of combinations is
If A = 7, then the number of combinations is
If A = 3, then the number of combinations is
Therefore, the total number of combinations is
Thus, the required number of different combinations is 120.
Learn more#
Question : ow many types of zygotic combinations are possible between a cross AaBBCcDd × AAbbCcDD?
Link : https://brainly.in/question/4909567.