S = the number of student tickets sold a = the number of adult tickets sold The drama class sold 25 more student tickets than adult tickets to the fall play s = a + 25 The class collected $660 from ticket sales: 6s + 3a = 660 divide both sides by 3 2s + a = 220 by solving the system of equations s = a + 25 2s + a = 220 we find s = 81.67 student tickets a = 56.67 adult tickets
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Answer:
which principle prevents a brach from abusing its power
Step-by-step explanation:
The answer can be readily calculated using a single variable, x:
Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%
The problem is then stated as:
(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000
Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.
Answer:
From top to bottom:
Step-by-step explanation:
We are given the piecewise function:
Row 1:
We want to find g(-2).
Since -2 is less than (or equal to) 2, we will use the first equation. Thus:
Row 2:
Likewise, 0 is less than or equal to 2. We will continue to use the first equation:
Row 3:
2 is not less than 2 but it is equal to 2. So we will continue to use the first equation:
Row 4 and 5:
Both 4 and 6 are greater than 2. Thus, we will use the second equation. Therefore:
Answer:
your answer is A
Step-by-step explanation:
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