-18 and +2
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Answer:
y -11 = 2(x -3)
Step-by-step explanation:
The slope of the given line is the x-coefficient: 2. The parallel line will have the same slope.
When you know the slope and a point on the line, it is convenient to use the point-slope form of the equation of a line:
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
Your line's equation is ...
y -11 = 2(x -3)
Hi!
When following the order of operations, A. Parantheses (or brackets) come first. =)
To solve this problem, we must imagine the triangles and
parallel lines which are formed. It is best to draw the triangle described in
the problem so that you can clearly understand what I will be talking about.
The first step we have to do is to make an equality equation
in triangle ABC.
In triangle ABC, we are given that lines XY and BC are two
parallel lines (XY || BC). Therefore
this means that:
AX / XB = AY / YC --->
1
The next step is to make an equality equation in triangle
AXC.
We are given that lines ZY and XC are two parallel lines (ZY
|| XC). Therefore this also means that:
AZ / ZX = AY / YC ---> 2
Combining 1 and 2 since they have both AY / YC in common:
AX / XB = AZ / ZX
we are given that:
AZ = 8, ZX = 4 therefore AX = AZ + ZX = 12, hence
12 / XB = 8 / 4
XB = 6