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3 years ago

Solve the equation 2.2 =z-1.1

Mathematics

2 answers:

Radda [10]3 years ago

7 0

Answer:

3.3

Step-by-step explanation:

In equations you must remember the important rule of keeping both sides balanced. If you do one operation to one side you must do it to the other, for example if you added 1.1 to the right side you must do it to the left side in order to keep the equation balanced so,

→ 2.2 = z - 1.1

⇒ Add 1.1 to both sides to isolate z

→ 3.3 = z

⇄ We can substitute 3.3 back into the equation to see if we have the right solution, if we get 2.2 on both sides then our solution is correct

→ 2.2 = z - 1.1

⇒ Substitute 3.3 into the equation

→ 2.2 = 3.3 - 1.1

⇒ Simplify

→ 2.2 = 2.2

Our solution of z = 3.3 is correct

Tresset [83]3 years ago

6 0

Answer:

Answer is 3.3 simplfly is 3.3 have good day

Step-by-step explanation:

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Andrew claims the initial value and y - intercept are the same thing on a graph. Is he correct?

Agata [3.3K]

Answer:

We conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

Step-by-step explanation:

We know that the initial value on a graph is basically the out-put value y of the point where the line meets or crosses the y-axis.

In other words, the initial value is the y-value or output of the point at x = 0

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the initial value of the equation y = 2x+1 is: y = 1

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Thus, at y = 1, the line meets the y-axis.

Hence, the initial value of the line is: y = 1

Similarly, we know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the y-intercept of y = 2x+1 is y = 1.

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Therefore, the y-intercept of y = 2x+1 is y = 1.

Conclusion:

Therefore, we conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

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