Answer:
The length of the midsegment is 9 ⇒ (B)
Step-by-step explanation:
In a triangle,
- The midsegment is the segment which joining the midpoints of two opposite sides of it
- The length of the midsegment is half the length of the third side in the triangle which opposite to it
<em>Let us use this rule to solve our question</em>
In Δ AC
∵ DE is the midsegment of it
∵ DE is opposite to the side AC
∴ The length of DE = 1/2 the length of AC
∵ The length of AC = 18
∴ The length of DE = 1/2 × 18
∴ The length of DE = 9
∴ The length of the midsegment is 9
The correct answer is B
Answer:
y = 2x^2 is a parabola opening up with it's vertex at (0,0)... y=3x^2 -4 is also a parabola opening up, but it is 'thinner' in that it rises in y faster and it's vertex is at (0,-4)
Step-by-step explanation:
all equations of the type y = ax^2 + b are parabolas centered on the y-axis, soo the vertex is always on (0,b)
If a is positive then the parabola opens up,
the bigger a is, the 'thinner' the graph is, i.e. the faster the graph rises
the value of b determines the location of the vertex, if b is added, then the vertex rises over the x-axis, if b is subtracted then the vertex is below the x-axis
Answer:
22
Step-by-step explanation:
Given that T is the midpoint of line PQ, segments PT = 5x + 2, and TQ = 7x - 6 that are formed would be equidistant or congruent. PT = TQ.
Therefore:
Let's find the value of x
Rearrange the equation, so that the terms having x would be on your left, while those without x would be on your right.
Divide both sides by -2
Plug in the value of x into the expression, 5x + 2, to find PT.
PT = 5(4) + 2 = 22.
Answer: 3x^2 + 7x -15
I dunno if u want me to factor it tho
Y = 1/2 x
for x = 0 → y = 1/2 · 0 = 0
for x = 2 → y = 1/2 · 2 = 1
x | 0 | 2 |
y=1/2x| 0 | 1 |
y = x + 3
for x = 0 → y = 0 + 3 = 3
for x = -3 → y = -3 + 3 = 0
x | 0 | 3 |
y=x+3|-3 | 0 |
