For this case, the first thing we must do is define variables:
x: unknown number (1)
y: unknown number (2)
We now write the equations that model the problem:
their sum is 6.1:
![x + y = 6.1 ](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D%206.1%0A)
their difference is 1.6:
![x - y = 1.6 ](https://tex.z-dn.net/?f=x%20-%20y%20%3D%201.6%0A)
Solving the system we have:
We add both equations:
![x + x = 6.1 + 1.6 2x = 7.7 x = 7.7 / 2 x = 3.85](https://tex.z-dn.net/?f=x%20%2B%20x%20%3D%206.1%20%2B%201.6%0A%0A2x%20%3D%207.7%0A%0Ax%20%3D%207.7%20%2F%202%0A%0Ax%20%3D%203.85)
Then, we look for the value of y using any of the equations:
Answer:
The numbers are:
<span>Let the nickels be x and the dimes be y
x + y = 24
5x + 10y = 185
5x + 5y = 120
5y = 65
y=13
x=11
Answer: 11 nickels and 5 dimes</span>
79.881 hope this helps
i might be wrong
Common ratio can be found by dividing the 2nd term by the first
r = 48/6
r = 8
an = a1 * r^(n-1)
n = term to find = 8
a1 = first number = 6
r = common ratio = 8
now we sub
a(8) = 6 * 8^(8-1)
a(8) = 6 * 8^7
a(8) = 6 * 2097152
a(8) = 12582912 <==
The formula for the amount A in an account with principal P and interest rate r compounded annually for t years is
... A(t) = P(1+r)^t
You want to find A when P=400, r=0.05, and t=3. Substituting those values gives you
... A(3) = 400·(1 +0.05)³
The appropriate choice is
... A. A(3) = 400·(1 +0.05)³