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ElenaW [278]
4 years ago
14

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. Show your work OR give an explaination.

Mathematics
1 answer:
IRINA_888 [86]4 years ago
8 0

Answer:

5x -20

Step-by-step explanation:

p(x) = r(x) - c(x)

      = 11x - (6x+20)

Distribute the minus sign

     = 11x -6x -20

Combine like terms

     = 5x -20

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(7-4) + 17 / -14 + 2 x 5
Yuliya22 [10]

Answer:

165/14

Step-by-step explanation:

(7-4) + 17 / -14 + 2 x 5

3 + 17/-14 + 2 x 5

3 - 17/14 + 2 x 5

3 - 17/14 + 10

165/14

8 0
3 years ago
Factor completely 4x5 − 20x4 − 36x3.
lakkis [162]

Answer:

the 2nd one is the answer :)

8 0
4 years ago
Three hundred high school seniors were surveyed about their intended college majors. The results are displayed in the Venn Diagr
atroni [7]

Answer: \frac{1}{10}

Step-by-step explanation:

Since, The total number of student = 300

Out of which,

The number of students who are only in Maths  = 120

And, The number of students who are only in Science  = 50

While, the students who are not from any subject = 100

Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None

= 300 - 120 - 50 - 100

= 30

That is, there are 30 students who are both from science and maths,

Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10

3 0
3 years ago
Read 2 more answers
Classify the model as Exponential GROWTH or DECAY.<br> A=1200(.85)6
BartSMP [9]

Answer: DECAY

Step-by-step explanation:

(.85) is less than 1

3 0
3 years ago
What is the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81?
Marizza181 [45]

Answer: d. 1.3333

Step-by-step explanation:

We know that the standard error of a sampling distribution is given by :-

S.E.=\dfrac{\sigma}{\sqrt{n}}

, where \sigma = Population standard deviation.

n= Sample size.

AS per given , we have

\sigma =12

n=81

Then, the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81 will be :-

S.E.=\dfrac{12}{\sqrt{81}}

=\dfrac{12}{\sqrt{9^2}}=\dfrac{12}{9}\\\\=\dfrac{4}{3}\\\\\approx1.3333

Hence, the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81 is 1.3333.

Thus the correct answer is d. 1.3333 .

6 0
3 years ago
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