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Crazy boy [7]
4 years ago
11

I'm not sure how to do this

Mathematics
1 answer:
VARVARA [1.3K]4 years ago
5 0
It's A because if you divide any number of hours and it's corresponding distance from data table shown in A by a number to get one hour you get a distance of 25 kilometers, for example ; 2 hours and 50 kilometers, divide it by 2 to get 1 hour and 25 kilometers. Or 6 hours and 150 kilometers divided by 6 to get 1 hour and 25 kilometers Therefore it is 25 kilometers per hour .
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What is 35 X (5 +150)=
ololo11 [35]

Answer: 5425

Step-by-step explanation:

7 0
3 years ago
Caroline wants to give 8 equal packets of sunflower seeds to her friends. She has 1/2 pound of sunflower seeds. How much will ea
zimovet [89]
What she has to do is divide her amount of sunflower seeds into the number of packages that she needs: so 1/2 pounds into 8:

\frac{1}{2}:8= \frac{1}{2*8}= \frac{1}{15}

-if we divide a fraction, we can multiply the denominator by the number we want to divide it by.


This is the correct answer, each packet will weight 1/15 of a pound, that is one ounce
3 0
3 years ago
Which solution to the equation 1/x-1=x-2/2x^2-2 is extraneous?
olga2289 [7]
<span>An extraneous solution is a solution, such as that to an equation, that emerges from the process of solving the problem but is not a valid solution to the original problem.

Given the equation:
\frac{1}{x-1} = \frac{x-2}{2x^2-2}  \\  \\ 2x^2-2=(x-1)(x-2)=x^2-3x+2 \\  \\ x^2+3x-4=0 \\  \\ (x-1)(x+4)=0 \\  \\ x-1=0 \ or \ x+4=0 \\  \\ x=1 \ or \ x=-4

From the equation, it is obtained that x = 1 and x = -4 are the solutions of the equation.

Now, we substitute x = 1 into the equation as follows:
</span><span>\frac{1}{1-1} = \frac{1-2}{2(1)^2-2}  \\  \\  \frac{1}{0} = \frac{-1}{2-2}  \\  \\  \frac{1}{0} = \frac{-1}{0}

As can be see, for x = 1, the equation is undefined.

Now, we substitute x = -4 into the equation as follows:
\frac{1}{-4-1} = \frac{-4-2}{2(-4)^2-2} \\  \\  \frac{1}{-5} = \frac{-6}{2(16)-2} = \frac{-6}{32-2} = \frac{-6}{30} \\  \\ - \frac{1}{5} =- \frac{1}{5}

It can be seen that x = -4 is a valid solution of the orignal equation.

Therefore, x = 1 is an extraneous solution to the equation
\frac{1}{x-1} = \frac{x-2}{2x^2-2}</span>
8 0
3 years ago
Need help with these ASAP
pychu [463]
Which one do you need help with ? Lmk
7 0
3 years ago
Lily's basketball team won 4/5 of their games. Lily scored points 2/3 of the games her team won. In waht fraction of her team's
igor_vitrenko [27]

\huge\fcolorbox{blue}{aqua}{Answer:}

════════════════════

Lily's basketball team won 4/5 of their games. Lily scored points 2/3 of the games her team won. In waht fraction of her team's winning games did Lily score points?

Answer: =D.\frac{5}{6}

Solution:

\frac{ 2  }{ 3  }   \div   \frac{ 4  }{ 5  }  =

\frac{2}{3}\times \left(\frac{5}{4}\right)

\frac{2\times 5}{3\times 4}

\frac{10}{12}

=\frac{5}{6}

I reduced the fraction \frac{10}{12} into the Lowest terms by doing extracting and cancelling out the 2

=\frac{5}{6}

So the answer is letter D.\frac{5}{6}

════════════════════

Explanation:

#Carry on learning

4 0
3 years ago
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