I need help on this question!! 15% of 9% is $__

X is a normally distributed random variable with mean 46 and standard deviation 22.

sesenic [268]

Answer:

B. 0.95

Step-by-step explanation:

The probability that the value of the random variable is in the given range is the area under the normal probability distribution curve over that range. The value of this area is conveniently provided by any number of calculators, apps, or spreadsheets. It can also be determined using the "empirical rule" that tells you the probability over certain normalized ranges.

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<h3>normalized range</h3>

A standard normal probability density function (PDF) has a mean of 0 and a standard deviation of 1. The range in this problem can be normalized to some number of standard deviations above or below the mean. The mean is given as 46, and the standard deviation is given as 22.

In this problem, the <em>lower limit</em> of the range is ...

z = (2 -46)/22 = -2

standard deviations from the mean.

Similarly, the <em>upper limit</em> is ...

z = (90 -46)/22 = +2

standard deviations from the mean.

<h3>empirical rule</h3>

The empirical rule tells us that 95% of the area of the PDF lies between -2 and +2 standard deviations from the mean.

P(2 < X < 90) ≈ 0.95

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<em>Additional comment</em>

The empirical rule for other ranges is ...

± 1 standard deviation: 68%

±2 standard deviations: 95%

±3 standard deviations: 99.7%

4 0

2 years ago

The crew of a garbage truck takes 5 hours to empty all the bins in one neighborhood on pickup day. The city assigned a second ga

iogann1982 [59]

Answer:

0.6

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Determine the volume of a cube with sides of 30mm

Svetllana [295]

Answer: Hello, your answer would be $2.7x10^-5m^3$

Step-by-step explanation:

$30mm$

$a=0.03m$

$V=a^3=0.03^3=2.7x10^-5m^3$

(the answer is also in the picture)

4 0

2 years ago

Read 2 more answers

Simplify and solve this equation 4m+9+5m-12=42

Ad libitum [116K]

Here is my answer. hope it helps!

8 0

4 years ago

Read 2 more answers

If you want to construct a 90% confidence interval, what critical value (z*) should you use? Group of answer choices 2.576 1.960

Rom4ik [11]

Answer:

For this case we know that the confidence level is 90% so then the significance level is $\alpha=1-0.9 =0.1$ and $\alpha/2 =0.05$ . And we can find in the normal standard distribution a value who accumulates 0.5 of the area on each tail and we got:

$z_{\alpha/2}= \pm 1.645$

And the best option would be:

1.645

Step-by-step explanation:

We assume that the parameter of interest is $\theta$ and we can assume that the distribution for this parameter is normally distributed so then the confidence interval assuming a two sided interval is given by:

$\hat \theta \pm z_{\alpha/2} SE$

Where $\hat \theta$ represent the estimator for the parameter, SE the standard error and $z_{\alpha/2}$ the critical value.

For this case we know that the confidence level is 90% so then the significance level is $\alpha=1-0.9 =0.1$ and $\alpha/2 =0.05$ . And we can find in the normal standard distribution a value who accumulates 0.5 of the area on each tail and we got:

$z_{\alpha/2}= \pm 1.645$

And the best option would be:

1.645

6 0

3 years ago

I need help on this question!! 15% of 9% is $___