Answer:
4/3 1.333 1 1/3
Step-by-step explanation:
Answer:
From what I can comprehend I believe the answer is <em>3.2x + -4</em>
Step-by-step explanation:
0.4(2x-9) = 0.8x - 9
0.8x - 9 - 0.6(4x+5)=
0.8x - 9 + 2.4x+5
0.8+2.4 = 3.2x
-9 + 5 = -4
3.2x + -4
4 x 5 - 3
= 20-3
=17<answer
Answer:
a =1 and a=4.
Step-by-step explanation:
The function is

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.
Now, for a a positive real we have that
will annulate the denominator, i.e
. But, if a = 1 we have:

so, the value
won't annulate the denominator.
Now, for a = 4 we have:

so, the value
won't annulate the denominator.
In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.
First step find a common multiple, e.g. 45 and subtract
9x + 5y = 28 * 5
5x + 9y = 56 * 9
45x + 25y = 140
-(45x + 81y = 504)
-56y = -364
56y = 364
y = 6.5
Substitute into any equation
9x + 5(6.5) = 28
9x + 32.5 = 28
9x = -4.5
x = -0.5
x = -0.5 , y = 6.5