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svetlana [45]
3 years ago
5

What are the high speed wind belt called ?

Chemistry
1 answer:
Leona [35]3 years ago
5 0

Answer:

It is called the jet stream.

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Transgender means that you got a gender change.
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4 years ago
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How many Cl atoms are in Zn(ClO3)2?<br> O A. 2<br> O B. 1<br> O c. 3<br> O D. 6
White raven [17]
The answer cl atoms are in zn(cio3)2 is A:2 because I looked it up and it gave me 2.
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The songs of birds are part of a ritual to attractpotential partners of their own species. The song presents specific patterns r
liberstina [14]

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Explanation:

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6 0
3 years ago
What volume of 1.5M NaOH is needed to provide 0.75 mol of NaOH?
lutik1710 [3]
1.5M NaOH so we've 1.5 moles of NaOH in 1L of solution

1L = 1000 ml

1.5 moles of NaOH ------------in------------- 1000 ml
0.75 moles of NaOH ----------in---------------x ml
x = 500 ml

<em><u>answer: C</u></em>
5 0
3 years ago
Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the
Alecsey [184]

Explanation:

The chemical equation is as follows.

      \frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)

And, the given enthalpy is as follows.

    \frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g);  \Delta H = 102.5 kJ

    Cl-Cl = 243 kJ/mol,      O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

   \Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}

    102.5 = [(\frac{1}{2})x + 498] - [(2)(243)]

    102.5 = (\frac{1}{2})x + 498 - 486

     102.5 - 12 = \frac{x}{2}

           x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

       \Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})

              x = [(\frac{1}{2})181 + (\frac{1}{2})498] - 243

                 = 339.5 - 243

                 = 96.5 kJ

Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

8 0
3 years ago
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