Answer:
0.0012 mol/L.
Explanation:
From the question given above, the following data were obtained:
Number of mole of AgNO₃ = 62.3 μmol
Volume = 50 mL
Molarity of AgNO₃ =?
Next, we shall convert 62.3 μmol to mole. This can be obtained as follow as follow:
1 μmol = 10¯⁶ mole
Therefore,
62.3 μmol = 62.3 × 10¯⁶
62.3 μmol = 62.3×10¯⁶ mole
Next, we shall convert 50 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
50 mL = 50 mL × 1 L / 1000 mL
50 mL = 0.05 L
Finally, we shall determine the concentration of AgNO₃ in mol/L as follow:
Number of mole of AgNO₃ = 62.3×10¯⁶ mole
Volume = 0.05 L
Molarity of AgNO₃ =?
Molarity = mole /Volume
Molarity of AgNO₃ = 62.3×10¯⁶ / 0.05
Molarity of AgNO₃ = 0.0012 mol/L
Thus, the concentration of AgNO₃ is 0.0012 mol/L
