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padilas [110]
3 years ago
6

2sinxcosx=sinx in the interval of [0,2pi]

Mathematics
1 answer:
Trava [24]3 years ago
5 0
Use the double angle function sin2x = 2sinxcosx.

2sinxcosx + sinx = 0

For the first part of the problem, consider the solutions on the interval where sinx = 0

x = 0, pi

Now consider the solutions where sinx does NOT equal zero.

2sinxcosx + sinx = 0

2sinxcosx = - sinx

2cosx = - 1

cosx = - 1/2

x = 2pi/3, 4pi/3
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Sunny_sXe [5.5K]
Ooh this is a good one!
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We could actually use 3 methods to find this side: 1) trig to find RT
2) trig to find ST, then Pythagorean Theorem to determine RT
3) use the special 30-60-90 right triangle rule ... hmm, I'm going with the last because it's easiest ;)

For 30-60-90 triangles, the sides are always as follows: smallest side (opposite the 30) is s, the middle side is sSR3, and the hypotenuse is 2×s
Thus, since we have the side opposite 60, it is = sSR3, so:
s \sqrt{3}  = 2 \sqrt{3}  \\ s \sqrt{3} \div  \sqrt{3}   = 2 \sqrt{3} \div  \sqrt{3}  \\ s = 2
So now, the hypotenuse (RT) = 2s = 2(2) = 4

Secondly, we are looking at the other type of special right triangle, the 45-45-90:
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we only need QR, which is s, which is also = RT
So the answer is:
QR = x = 4

x = 4 IS THE FINAL ANSWER!!!


[ i hope by my explanations you understand how better to do special right triangles in the future] :-D
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Step-by-step explanation:

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Answer:

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lapo4ka [179]

Answer:

c = -6

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Step-by-step explanation:

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