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1 answer:
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Answer:
There are 6.024 grams of sodium hydroxide in the solution.
Explanation:
Moles of sodium hydroxide = n
Volume of sodium hydroxide solution = 251.0 mL = 0.251 L
Molarity of the sodium hydroxide = 0.600 M
Mass of 0.1506 moles of NaOH :
There are 6.024 grams of sodium hydroxide in the solution.
Question options:
a) 2.05
b) 0.963
c) 0.955
d) 1.00
Answer:
b) 0.963
Explanation:
H2SO4→ HSO4- + H3O+
HSO4- + H2O ⇌ SO42- + H3O+
Construct ICE table:
HSO4- (aq) + H2O ⇌ SO42- (aq) + H3O+ (aq)
I 0.1 solid & 0 0.1
C -x liquid + x + x
E 0.1 - x are ignored x 0.1 + x
Calculate x
Ka = products/reactants
=
0.011 =
0.011 x (0.1 -x) = o.1x + x^2
0.0011 - 0.011 x - o.1x - x^2 = 0
0.0011 - 0.011 x - x^2 = 0
Use formula to solve for quadratic equation
x = / 2a
a = -1, b = -0.111, c = 0.001
Solve for x
x = / 2(-1)
x = 0.111 +,- / -2
x = 0.111 +,- / -2
x =
x = , x =
x = , x =
x = - 0.12015 , x = 0.00915
x cannot be negative, so
x = 0.00915 M
Calculate [H3O+]
[H3O+] = 0.1 M + x
[H3O+] = 0.1 M + 0.00915 M
[H3O+] = 0.10915 M
Clculate pH
pH = - log [ H3O+]
pH = - log [ 0.10915]
pH = 0.963