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USPshnik [31]
3 years ago
5

Relationships among Species X Y Boxing crabs gently carry anemones in their claws to sting predators and keep them away. The ane

mones feed off bits of food the crab drops. Fleas live on the warm body of a dog, biting the dog and eating its blood. The flea bites cause the dog to itch. Which headings best complete the chart? X: Competition Y: Parasitism X: Competition Y: Commensalism X:Commensalism Y: Mutualism X: Mutualism Y: Parasitism
Biology
2 answers:
Trava [24]3 years ago
8 0

Answer:

idk for sure but here

Explanation:

a chart to describe some relationships among species. Relationships among Species X Y Boxing crabs gently carry anemones in their claws to sting predators and keep them away. The anemones feed off bits of food the crab drops. Fleas live on the warm body of a dog, biting the dog and eating its blood.

stealth61 [152]3 years ago
4 0

Answer: X: Mutualism  Y: Parasitism

Explanation:

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3 years ago
Please help m with my homework (keep it simple ,and i am sorry i didnt find the science)
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7 0
3 years ago
1: Parents can pass down many traits to their children. All BUT one of the following can be passed down. That is A) freckles. B)
siniylev [52]

1: B

2: C

3: B

4: Either A or B

8 0
4 years ago
A new kind of tulip is produced that develops only purple or pink flowers. Assume that flower color is controlled by a single-ge
Sophie [7]

Answer:

a. purple allele (C) = 0.609, pink allele (c) = 0.391

b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476

Explanation:

Given -

Purple flowers - 847

Pink flowers - 153

The frequency of recessive genotype i.e

q^ 2 = \frac{153}{1000} \\q^ 2 = 0.153\\

Frequency of recessive allele i.e q is equal to

q = \sqrt{0.153} \\q = 0.391

As per hardy Weinberg's first equilibrium equation -

p + q = 1\\p = 1-q\\p = 1-0.391\\p = 0.609

Frequency of purple homozygous species

= p^2\\= 0.609^2\\= 0.371

Number of purple homozygous species = 0.371 * 1000= 371

Number of pink homozygous species = 0.153 * 1000= 153

Heterozygous species is equal to

(1-0.371-0.153)* 1000\\= 0.476 * 1000\\= 476

5 0
3 years ago
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BlackZzzverrR [31]
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