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Katena32 [7]
3 years ago
11

Identify the center and radius of each. Photo attached.

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Answer:

<em>Center ~ ( -4, 3 ), Radius ~ 2; Option A</em>

Step-by-step explanation:

<em>~ We know that the standard circle equation ( x - a )^2 + ( y - b )^2 = r^2  provided r ⇒ radius of the circle, centered at ( a, b ) ~</em>

1. If we are given the circle formula ( x + 4 )^2 + ( y - 3 )^2 = 4, it would be that the center points ( a, b ) would be the inverse of 4 and -3, provided the formula is -a and -b: center ( -4, 3 )

2. Now the radius in the formula ( x - a )^2 + ( y - b )^2 = r^2, is noted by r such that in ( x + 4 )^2 + ( y - 3 )^2 = 4, r^2 is 4 ⇒ r = √4 = 2

3. We now know that the center of this circle is ( -4, 3 ) with a radius of 2, and the only graph that represents that function is the first graph ~

<em>Answer: Center ~ ( -4, 3 ), Radius ~ 2</em>

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STEP-BY-STEP EXPLANATION:
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What is 1.75 kilometres as a fraction of 700 metres? <br>Give your answer in its simplest form​
aniked [119]

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5/2

Step-by-step explanation:

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7 0
3 years ago
A. [4 marks]
storchak [24]

The value of d is -2

Step-by-step explanation:

The nth term of the arithmetic sequence is u_{n}=u_{1}+(n-1)d , where

  • u_{1} is the first term
  • d is the common difference between each 2 consecutive terms

The nth term of the geometric sequence is u_{n}=u_{1}r^{n-1} , where

  • u_{1} is the first term
  • r is the common ratio between each two consecutive terms r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}

∵ u_{1} of an arithmetic sequence is 1

∵ The common difference is d, where d ≠ 0

∵ u_{2} , u_{3} , u_{6} are the first 3 terms of a geometric sequence

∵ u_{2} = 1 + (2 - 1)d

∴ u_{2} = 1 + d

∵ u_{3} = 1 + (3 - 1)d

∴ u_{2} = 1 + 2d

∵ u_{6} = 1 + (6 - 1)d

∴ u_{2} = 1 + 5d

∴ The first 3 terms of the geometric sequence are (1 + d) , (1 + 2d) ,

   (1 + 5d)

∵ The common ratio in the geometric sequence is r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}

∴ r=\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}

- Use cross multiplication with the equal fractions

∵ \frac{1+2d}{1+d}=\frac{1+5d}{1+2d}

∴ (1 + 2d)(1 + 2d) = (1 + d)(1 + 5d)

∴ 1 + 2d + 2d + 4d² = 1 + 5d + d + 5d²

- Add like terms in each side

∴ 1 + 4d + 4d² = 1 + 6d + 5d²

- Subtract 1 from both sides

∴ 4d + 4d² = 6d + 5d²

- Subtract 4d from both sides

∴ 4d² = 2d + 5d²

- Subtract 4d² from each side

∴ 0 = 2d + d²

- Take d as a common factor

∴ 0 = d(2 + d)

- Equate each factor by 0

∴ d = 0 but we will reject it because d ≠ 0

∴ 2 + d = 0

- Subtract 2 from both sides

∴ d = -2

The value of d is -2

Learn more:

You can learn more about the sequence in brainly.com/question/1522572

#LearnwithBrainly

7 0
3 years ago
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Mrac [35]
Value of the boat after 9 years= 12050*(1-0.12)^9
=$3814(correct to nearest integer)
8 0
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