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Damm [24]
2 years ago
6

Find the explicit formula for 15, 12, 9, 6,

Mathematics
1 answer:
QveST [7]2 years ago
6 0

Answer:

D

Step-by-step explanation:

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How do you turn .15 repeating into a fraction show work
mafiozo [28]

0.15 as a fraction would be 3 over 20 or 3/20. Hope this helps! Plz mark me as brainliest!!! :)

7 0
3 years ago
NEED HELP WITH THESE QUESTIONS
amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =

Applying double C we have:

\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =

By definition of multiplication of powers of the same base we have to place the same base and add the exponents:\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =

Canceling common terms:

\frac {mn ^ 5} {p ^ 4}

Answer:

Option A

Question 2:

We should simplify the following expression:

\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}

So, we have:

\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =

Simplifying common terms:

\frac {1} {y ^ 2z ^ 2}

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

<em>r ^ 2 + 7r + 10: </em>We look for two numbers that multiplied give 10 and added 7:

(r + 5) (r + 2)

<em>r ^ 2-5r-50:</em> We look for two numbers that multiplied give -50 and added -5:

(r-10) (r + 5)

<em>3r-30 = 3 (r-10)</em>

Rewriting the given expression we have:

\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =

We simplify common terms in the numerator and denominator we have:

(r + 2)

Answer:

Option D

4 0
3 years ago
Read 2 more answers
the number of kilometers a car can drive varies directly with the liters of fuel in the car. this car can travel 476 kilometers
notka56 [123]

For this case we have that the relationship is direct.

Therefore, we have:

y = k * x

Where,

y: distance traveled in kilometers

x: number of liters of fuel

k: proportionality constant

We must look for the value of k. For this, we use the following data:

This car can travel 476 kilometers on 17 liters of fuel.

Substituting values we have:

476 = k * 17

From here, we clear the value of k:

k = \frac{476}{17}\\k = 28

Therefore, the relationship is:

y = 28x

For 1428 kilometers we have:

1428 = 28x

Clearing the amount of fuel we have:

x = \frac{1428}{28}\\x = 51

Answer:

51 liters of fuel are required for the vehicle to travel 1,428 kilometers

3 0
3 years ago
What is equivalent too 48j +36
Nata [24]
84j is the equivalent.
Just add 36 to 48 and put the j on.
7 0
2 years ago
Answer and explanation plz ???
Nutka1998 [239]

Answer:

25

Step-by-step explanation:

Formula

2xy + 1

Givens

x = 3

y = 4

Solve

2*(3)*(4) + 1

24 + 1

25

7 0
3 years ago
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