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3 years ago

Find the value of x in the question

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

4 0

Answer:

x=52

Step-by-step explanation:

r=90 s=34 q=180-(90+34)

180-(90+34)=56

to find angle sqr

180-56=124

124=x+72

52=x

disa [49]3 years ago

3 0

Answer:

x = 52

Step-by-step explanation:

→We are given an exterior angle (outside of the triangle) as (x + 72). We are also given two interior angles as 34 and 90. The sum of the two farthest interior angles away from the exterior, is equal to the exterior. So this means that ∠R(90°) + ∠S(34°) = ∠PQS(x + 72), and we can set up the equation like that:

90 + 34 = x + 72

<u>→Add like terms (90 and 34):</u>

124 = x + 72

<u>→Subtract 72 from both sides:</u>

52 = x

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4x – 7 = 5x + 2<br> What is X?

Maksim231197 [3]

Answer:

x = -9

Step-by-step explanation:

We are solving for x

Subtract 2 from both sides and you get:

4x - 9 = 5x

Then subtract 4x from both sides:

-9 = x

5 0

3 years ago

Read 2 more answers

Let an be the sum of the first n positive odd integers.

sesenic [268]

Answer:

A) The first 4 terms of the sequences are: $a_{1} =16$ , $a_{2} =24$ , $a_{3} =32$ and $a_{4} =40$ .

B) An explicit formula for this sequence can be written as: $a_{n} =8*(n+1)$

C) A recursive formula for this sequence can be written as:

$\left \{ {{a_{1} =16} \atop {a_{n} =a_{n-1}+8}} \right.$

Step-by-step explanation:

A) You can find the firs terms of this sequence simply selecting an odd integer and summing the consecutive 3 ones:

$a_{n} = Odd_{n}+Odd_{n+1}+Odd_{n+2}+Odd_{n+3}$ (a.1)

$a_{1}=1+3+5+7=16$

$a_{2}=3+5+7+9=24$

$a_{3}=5+7+9+11=32$

$a_{4}=7+9+11+13=40$

B) Observe the sequence of odd numbers 1, 3, 5, 7, 9, 11, 13(...).

You can express this sequence as:

$Odd_{n}=(2*n-1)$ (b.1)

If you merge the expression b.1 in a.1, you obtain the explicit formula of the sequence:

$a_{n} = Odd_{n}+Odd_{n+1}+Odd_{n+2}+Odd_{n+3}$ (a.1)

$a_{n} = (2*n-1)+((2*(n+1)-1))+((2*(n+2)-1))+((2*(n+3)-1))$ (b.2)

$a_{n} = 8*n+8$ (b.3)

$a_{n} =8*(n+1)$ (b.s)

C) The recursive formula has to be written considering an initial term and an N term linked with the previous term. You can see an addition of 8 between a term and the next one. So you can express each term as an addition of 8 with the previous one. Therefore, if the first term is 16:

$\left \{ {{a_{1} =16} \atop {a_{n} =a_{n-1}+8}} \right.$ (c.s)

5 0

3 years ago

A certain bowler can bowl a strike 85 % of the time. What is the probability that she a) goes three consecutive frames without

Artist 52 [7]

Answer:

a) 0.34% probability that she goes three consecutive frames without a strike.

b) 1.91% probability that she her first strike in the third frame

c) 99.66% probability that she has at least one strike in the first three frames.

d) 14.22% probability that she bowls a perfect game.

Step-by-step explanation:

For each frame, there are only two possible outcomes. Either there is a strike, or there is not. The probability of a strike happening in a frame is independent of other frames. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A certain bowler can bowl a strike 85 % of the time.

This means that $p = 0.85$

a) goes three consecutive frames without a strike?

This is $P(X = 0)$ when $n = 3$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.85)^{0}.(0.15)^{3} = 0.0034$

0.34% probability that she goes three consecutive frames without a strike.

b) makes her first strike in the third frame?

No strike during the first two(with a 15% probability)

Strike during the third(85% probability). So

P = 0.15*0.15*0.85 = 0.0191

1.91% probability that she her first strike in the third frame

c) has at least one strike in the first three frames? 

Either there are no strikes, or there is at least one strike. The sum of the probabilities of these events is 100%.

From a), 0.34% probability that she goes three consecutive frames without a strike.

100 - 0.34 = 99.66

99.66% probability that she has at least one strike in the first three frames.

d) bowls a perfect game (12 consecutive strikes)?

This is $P(X = 12)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{12,12}.(0.85)^{12}.(0.15)^{0} = 0.1422$

14.22% probability that she bowls a perfect game.

3 0

4 years ago

Use the distributive property 5(z+ 2) to rewrite this expression

Agata [3.3K]

You have to multiply everything inside the parentheses by 5.
So it will look like this
5z+10

6 0

3 years ago

No. 7 help me Whoever answer i will brainly you. You will got 15 points

Sedaia [141]

<h2>360 numbers can be made!</h2><h2>The thousands place is filled 6 ways; the hundreds place is filled 5 ways; the tens place is filled 4 ways; the ones place is filled 3 ways.</h2><h2>Multiply the numbers together:</h2><h2>6*5*4*3=360</h2>

7 0

3 years ago