Robert is lying on the ground, looking at the top of a flagpole. The angle of elevation to the top of the flagpole is 25°. What is the height of the flagpole if the distance from his eyes at the ground to the base of the flagpole is 200 ft?
1 answer:
Answer:
height of the flagpole = 93.26 ft
Step-by-step explanation:
The illustration forms a right angle triangle. The angle of elevation from his eyes to the flag is 25° . The distance from his eyes at the ground to the base of the flagpole is 200 ft.
The adjacent side of the triangle formed is the distance of his eyes from the flagpole. The height of the flagpole is the opposite side of the right angle triangle formed.
using tangential ratio
tan 25° = opposite/adjacent
tan 25° = x/200
cross multiply
200 tan 25° = x
x = 200 × 0.46630765815
x = 93.261531631
x = 93.26 ft
height of the flagpole = 93.26 ft
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