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3 years ago

Please help with this graph

Mathematics

1 answer:

Lina20 [59]3 years ago

7 0

The answer is true because it comes at an angle which is adjacent to what needs to be the answer
Hoped this helped

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Mr.Hollins determines that he gives away $800 each month. If he gives away 16% of his budget, how much is his overall budget?

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$\frac{800}{x} = \frac{16\%}{100\%} \\ \frac{80000}{16} = \frac{16x}{16} \\ 5000 = x$

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3 years ago

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a triangle pyramid has lateral faces with bases of 6meters and hights of 9 meters the area of the base of the pyramid

Alexxandr [17]

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3 years ago

ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?

MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = $\sqrt{(x_2-x_1)^2 +( y_2-y_1)^2$

Step 1: Finding the length of EF

By using distance formula,

$EF = \sqrt{(-7 - 0)^2 + (4-0)^2}$

$EF = \sqrt{(49) + (16)}$

$EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\$

Step 2: Finding the length of FG

By using distance formula,

$FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}$

Step 2: Finding the length of GE

$GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8$

Thus we could see that the sides EF = FG

So it is a isosceles triangle.

6 0

3 years ago

For each figure answer the following questions

Rudiy27

9514 1404 393

Answer:

a) ∆ABC ~ ∆EDC by AA similarity

b) ED/AB = 3/4

c) 15 cm

Step-by-step explanation:

a) Two angles in each triangle are the same, so the AA similarity postulate can be used to declare the ∆ABC ~ ∆EDC. (Each triangle includes a right angle and angle C.)

b) Corresponding sides are ED/AB, DC/BC, EC/AC. The ratio of corresponding sides is ED/BC = (12 cm)/(16 cm) = 3/4.

c) Using the ratios identified above, we have ...

DC/BC = 3/4 = x/(20 cm)

x = 3/4(20 cm)

x = 15 cm

8 0

3 years ago