Answer:
0.7 = 70%.
Step-by-step explanation:
There are 5 cans, and she will pick 2, so the number of possibilities that she can pick 2 cans is a combination of 5 choose 2:
C(5,2) = 5!(3!*2!) = 5*4/2 = 10
To find how many possibilities there are with at least 1 can of soup, we can find the number of groups that include no cans of soup, and then see how many possibilities complete the total 10:
There are 3 "no-soup" cans, so the number of possibilities is a combination of 3 choose 2:
C(3,2) = 3!/2! = 3
So, there are 3 possibilities that have no cans of soup, so the number of possibilities that have at least 1 can of soup is 10 - 3 = 7
Then, the probability is 7 / 10 = 0.7 = 70%.
Answer:
a. 5,040 ways
b. 210 ways
Step-by-step explanation:
a) We want to pick 4 numbers out of 10 given that orders matter
If orders do matter, it will be a permutation problem
Mathematically;
n P r = n!/(n-r)!
In this case, n is 10 and r is 4
Thus, we have it that;
10 P 4 = 10!/(10-4)! = 5,040
b) if orders do not matter
It will be a combination problem
n C r = n!/(n-r)!r!
n = 10 and r = 4
10 C 4 = 10! /(10-4)!4!
= 210
Answer:
Ron has 15 nickels and 9 quarters
Step-by-step explanation:
Create a system of equations where n is the number of nickels and q is the number of quarters he has:
n + q = 24
0.05n + 0.25q = 3
Solve by elimination by multiplying the top equation by -0.25
-0.25n - 0.25q = -6
0.05n + 0.25q = 3
Add them together and solve for n:
-0.2n = -3
n = 15
So, Ron has 15 nickels. Find how many quarters he has by subtracting 15 from 24:
24 - 15
= 9
So, Ron has 15 nickels and 9 quarters.
