Both distances 3966 and 4746 were done in 6 hours, so the speeds are:
speed against wind = 3966/6=661 km/h (difference of airplane and wind)
speed with wind = 4746/6=791 km/h (sum of airplane and wind)
The speed of airplane is greater than that of the wind, so this is a sum and difference problem.
Greater speed (plane) = (sum+difference)/2=(791+661)/2=726 km/h
Lesser speed (wind) = (sum-difference)/2 = (791-661)/2 = 65 km/h
<span>In general, the students increased their standardized math scores from 5th grade to 7th grade. The students might be more familiar with the exam and they have learned more in their math classes.</span>
1 hour = 60 minutes = 3600 seconds = 1/24 day
Divide every number above by 2 to get 1/2 hour and its equivalent numbers.
1/2 hour = 30 minutes = 1800 seconds = 1/12 day
