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8090 [49]
3 years ago
10

An angle measures 120 degrees. Describe how to use special right triangles and the unit circle as tools to calculate the sine an

d cosine of this angle.
Mathematics
1 answer:
nalin [4]3 years ago
8 0

Answer:

120 degrees is the right angle and the 30 degree added which is 1/3 here we know as we can always divide a side measure by 90 then multiply by a second angle to find the hypotenuse. When we do this we are using a three way system just like a three way system appears when we use a right angle triangle and read the functions.

Step-by-step explanation:

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(-1.1)^13 x (-1.1)^12 / (-1.1)^10 x (-1.1)^1
olga nikolaevna [1]

Answer:

15.455

Step-by-step explanation:

3 0
4 years ago
Question 3 (open to see pic)
melamori03 [73]
The points (1,-2) and (4,16) are not in the line but the point (-3,-18) is on the line. (Work is shown in the image)

8 0
3 years ago
Is this positive, negative, none or you cannot tell. Will mark CORRECT brainliest
pshichka [43]

Answer:

Positive correlation if right. Atleast consider brainlist:)

Step-by-step explanation:

3 0
3 years ago
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Jamal's lawn is shaped like a square with an area of 224.9 ft? Which measurement is closest to the side length of
abruzzese [7]

Answer:

Square root of 224.9 is very close to 15.

So the lawn is 15 by 15.

Step-by-step explanation:

6 0
3 years ago
True or false <br><br> (Picture provided)
aksik [14]
<h2>Answer:</h2><h3>False</h3><h2>Step-by-step explanation:</h2>

Let's find the inverse function of f(x)=(x-3)^3+4 to know whether this function has an inverse function f^{-1}(x)=-3+\sqrt[3]{x+4}. So let's apply this steps:

a) Use the Horizontal Line Test to decide whether f has an inverse function.

Given that f(x) is a cubic function there is no any horizontal line that intersects the graph of f at more than one point. Thus, the function is one-to-one and has an inverse function.

b) Replace f(x) by y in the equation for f(x).

y=(x-3)^3+4

c) Interchange the roles of x and y and solve for y

x=(y-3)^3+4 \\ \\ \therefore x-4=(y-3)^3 \\ \\ \therefore (y-3)^3=x-4 \\ \\ \therefore y-3=\sqrt[3]{x-4} \\ \\ \therefore y=\sqrt[3]{x-4}+3

d) Replace y by f^{-1}(x) in the new equation.

f^{-1}(x)=\sqrt[3]{x-4}+3

So this is in fact the inverse function and it isn't the same given function. Therefore, the statement is false

3 0
4 years ago
Read 2 more answers
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