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8090 [49]
3 years ago
10

An angle measures 120 degrees. Describe how to use special right triangles and the unit circle as tools to calculate the sine an

d cosine of this angle.
Mathematics
1 answer:
nalin [4]3 years ago
8 0

Answer:

120 degrees is the right angle and the 30 degree added which is 1/3 here we know as we can always divide a side measure by 90 then multiply by a second angle to find the hypotenuse. When we do this we are using a three way system just like a three way system appears when we use a right angle triangle and read the functions.

Step-by-step explanation:

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Solve each equation by substitution
Aneli [31]

Answer:

<em>(1, 7) </em>

Step-by-step explanation:

y = 3x + 4

y = 6x + 1

6x + 1 = 3x + 4 ⇒ x = 1

y = 3(1) + 4 = 7

<em>(1, 7)</em>

4 0
3 years ago
Read 2 more answers
2. If a= 2, b= 3 and c= 3,evaluate: i) a+ 2b ii) a+b+c​
scoundrel [369]

Answer:

i)a + 2b = 2 + 2(3) = 2 + 6 = 8 \\ ii)a + b + c = 2 + 3 + 3 = 2 + 6 = 8

7 0
2 years ago
Read 2 more answers
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
Which fraction is the smallest 1/2 1/3 5/8 6/14
jek_recluse [69]
The answer is 6/14 , this should be correct because it has 14 sections which makes it smaller than the rest!
6 0
3 years ago
How many times can 1000000000000 go into 10
makkiz [27]

Answer:

10 million (10,000,000) tens can go into 100,000,000

Step-by-step explanation:

4 0
3 years ago
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