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3 years ago

14

Dr. Hung prescribed 0.019 L more medicine then Dr. tannenbaum Dr. Evans prescribe 0.02 was the one Doctor Who prescribed the mos

t who prescribed the lease

1 answer:

arlik [135]3 years ago

4 0

Dr. Evans prescribed more. Dr. Hung prescribed less. 0.019 < 0.02

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Joseph has started completing the square on the equation 3x^2-7x+12=0. He has worked to the point where he has the expression x^

Dima020 [189]

Starting with <span>3x^2-7x+12=0, we divide all four terms by 3, resulting in the following factored form:
</span><span>
3(</span><span>x^2-[7/3]x+4)=0.
</span><span>
Since 3 cannot equal 0, we can focus on the following:

x^2 - 7/4 x =-4

This completes the assignment (describe Joe's steps up to this point).

If you wish to go further:

Next, take HALF of the coefficient of x and square your result:

(-7/[4][2])^2 = 49/64

Add this to both sides of </span>x^2 - 7/4 x =-4: <span>x^2 - 7/4x + 49/64 =-4+49/64

Rewrite the left side as (x-7/8)^2 and the right side as 49/64 - 256/64

Simplify the right side by combining these terms: -207/64

Then x-7/8 = plus or minus (1/8)sqrt(-207)

Next, x = 7/8 plus or minus (1/8)*i*</span>√207, or

7 plus or minus i*√207
x = ----------------------------------
8

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3 years ago

If right I’ll mark brainiest

RUDIKE [14]

Answer: See explanation

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2 years ago

Question 7 (1 point)

svetlana [45]

Answer:

V=lwh=5 x 9 x 3=135cm+33=4

Step-by-step explanation:

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2 years ago

Write the number in standard notation. 4.16 *10^-5 0.00000416 0.0000416 0.000416 –208

zalisa [80]

$4.16\cdot10^{-5}\\\\move\ the\ decimal\ 5\ place\ left\\\\4.16\cdot10^{-5}=0.0000416$

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3 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago