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zheka24 [161]
3 years ago
8

Find the value of x in the triangle shown below.

Mathematics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

x=69.41860973

Step-by-step explanation:

We can use the law of sines

sin x             sin 55

------------- = -----------

4                       3.5

Using cross products

3.5 sin x = 4 sin 55

Divide each side by 3.5

sin x = 4/3.5 sin 55

Take the inverse sin of each side

x = sin ^-1 ( 4/3.5 sin 55)

x=69.41860973

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spayn [35]
1303/12.8 is the answer for that one which it should land in the middle of the line!
6 0
3 years ago
Someone help me with this ASAP
romanna [79]

Answer:

<em>Circumference:</em> 18.84 cm

<em>Area:</em> 28.26 cm^2 (exponent 2)

Step-by-step explanation:

Circumference = 2(pi)r

The diameter is 6. Means the radius is 3 (half of 6)

pi = 3.14

2(3.14) x 3 = 18.84

Circumference is 18.84 cm.

Area of a circle = (pi)r^2

(3.14)(3)^2 = 28.26 cm^2 (exponent 2)

6 0
3 years ago
$57.66 is 70% of what total number?
Paha777 [63]

Answer:

74.958

Step-by-step explanation:

Because 57.66 added 30 percent is equal to 74.958

7 0
4 years ago
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
4 years ago
Write 98 as the product of prime factors in ascending order
umka2103 [35]

to write 98 as a product of its prime factors we have to first find the prime factors of 98

prime factors are prime numbers by which the given number can be divided by.

98 we have to keep dividing it by prime numbers

98 is an even number so we can first divide by 2

98 / 2 = 49

49 is a multiple of 7 which too is a prime number so we can divide 49 by 7

49/7 = 7

7 can be divided again by 1

7/7 = 1

98 is divisible by 2 and 7

so 98 written as a product of prime factors is

98 = 2 x 7 x 7

4 0
3 years ago
Read 2 more answers
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