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Andru [333]
3 years ago
9

A student was required to multiply a number by 4 and add 6 to it. Instead he added 6 to it first and then multiplied by 4. What

should he do to his answer to get the correct one? If the wrong answer is 36, what is the correct one?
Answer:

If n is the number, the wrong expression is :

.

The correct expression is :

.

He needs to the wrong expression to get the correct one.

The correct answer is

.
Mathematics
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

The correct answer is 18

the correct expression is (4n+6)

Step-by-step explanation:

let the number be n

therefore  if he is required to multiply n by 4 and added to 6 we have

(4n+6)= 0-----1

given that he did otherwise by adding 6 to n and multiply by 4 we have

(n+6)4= 36------2

Firstly we need to solve for n in equation 2

4n+24= 36\\4n= 36-24\\4n= 12\\

Dividing both sides by 4 we have

n= \frac{12}{4\\}\\n= 3

In order to solve for the correct answer let us input n=3 in equation 1 we have

=(4n+6)= 0-------1\\=(4*3+6)= 0\\=(12+6)=0\\= 18

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3 years ago
Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
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