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3 years ago

Match the numbers with the LCM.

Mathematics

1 answer:

sergiy2304 [10]3 years ago

4 0

Answer: 1- 36 and 45 LCM is 180

2- 42 and 105 LCM is 210

3- 254 and 231. I kept on getting 58674 so I don’t really know what the answer is, sorry

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Justin is on a road trip. Over the past two days, he’s driven a total distance of 504 miles at an average speed of 56 miles/hour

irakobra [83]

Recall d = rt, distance = rate * time.

now, he has a speed rate of 56 mph for a distance of 504

$\bf d=rt\implies 504=56t\implies \cfrac{504}{56}=t\implies \stackrel{hours}{9}=t$

so, at that speed the whole driving time is 9 hours then. Ok, he drove 2 hours today, that means he drove 7 yesterday, 9 - 2.

how many miles is it for 7 hours at 56mph? d = rt ---> d = 56 * 7

that many miles he drove yesterday.

8 0

3 years ago

PLEASE HELP!!!!!! who every gets it right I will give brainly and 20 points

Sindrei [870]

Unit price:

$3.03 for a gallon of gass

$0.05 per ounce of soap

$0.75 per bag of popcorn

Not a Unit Price:

$20 for 5 books

$33.00 for 2 avocadoes

hoped that helped

8 0

2 years ago

3. Quincy deposits $400 in a new bank account that earns 4% simple interest per year. What

Illusion [34]

Answer:

$448

Step-by-step explanation:

We can use the simple interest formula for this:

$A = P (1 + rt)$

P = initial balance

r = annual interest rate

t = time

First, change 4% into its decimal form:

4% -> $\frac{4}{100}$ -> 0.04

Now, lets plug in the values:

$A=400(1+(0.04)(3))$

$A=448$

The total amount in the account after 3 years will be $448

8 0

3 years ago

9 minutes =how many seconds

iogann1982 [59]

there is 60 seconds in 1 min so if you do 60x9 you should get 540

glad to help!

7 0

3 years ago

Tires have a normal distribution with a mean of 70000 miles and a standard deviation of 4400 miles. What proportion of tires wil

yarga [219]

Let T = the distance, in miles, a tire lasts

T ~ N(70000,4400²)

P(T $\geq$ 75000)
= P(Z $\geq \frac{75000 - 70000}{4400}$ )
= P(Z $\geq \frac{25}{22}$ )
≈ P(Z $\geq$ 1.14)
= 1 - P(Z < 1.14)
≈ 1 - 0.8729
= 0.1271

5 0

3 years ago