All categories

2 years ago

12. The mean number of boxes of cookies sold by

Mathematics

1 answer:

rjkz [21]2 years ago

8 0

Answer:

Step-by-step explanation:

i hope this help you

You might be interested in

4(y+6)+5y this irritating

Alla [95]

I'm guessing you have to simplify this?
You distribute 4 to whatever is in the parenthesis.

So
4•y=4y
4•6=24
And of course there's the 5y that stays the same.

You get 4y+24+5y
Which simplifies to 9y+24 because you can group the 4y and 5y together.

In the end, you get 9y+24.

4 0

3 years ago

F(x) = 4x + 3. f(5) = 23. Which number is the input?

Oksanka [162]

B. 5 is the input

Step-by-step explanation:

f(x) = 4x + 3 f(5) = 23 Plug in 5 for x.

f(x) = 4(5) + 3

f(x) = 20 + 3

f(x) = 23

B. 5 is the input

3 0

3 years ago

Read 2 more answers

gary has $227.36 in his bank account. her must maintain a minimum balance of $550 in his account to avoid paying monthly service

tia_tia [17]

Answer:322.64 (I think)

Step-by-step explanation:

550-227.36=322.64

6 0

3 years ago

Read 2 more answers

Repost: Каков объем этой прямоугольной призмы?

torisob [31]

So first of all we should know that the <u>rectangular prism is a cuboid.</u>

$\\ \\$

<h3>Given :-</h3>

heigth = 9 in.
Length = 5 in.
Width = 4 in.

$\\$

Volume of cuboid.

$\\$

<h3>Solution:-</h3>

We know:-

$\bigstar \boxed{ \rm volume \: of \: cuboid = length \times width \times height}$

$\\ \\$

So:-

$\dashrightarrow \sf volume \: of \: cuboid = length \times width \times height \\$

$\\ \\$

$\dashrightarrow \sf volume \: of \: cuboid = 9 \times 5 \times 4 \\$

$\\ \\$

$\dashrightarrow \sf volume \: of \: cuboid = 45 \times 4 \\$

$\\ \\$

$\dashrightarrow \bf volume \: of \: cuboid = 180 {in}^{3} \\$

Therefore option C is correct .

$\\ \\$

$\\ \\$

$\begin{gathered}\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{CSA_{(cylinder)} = 2\pi \: rh}\\ \\ \bigstar \: \bf{Volume_{(cylinder)} = \pi {r}^{2} h}\\ \\ \bigstar \: \bf{TSA_{(cylinder)} = 2\pi \: r(r + h)}\\ \\ \bigstar \: \bf{CSA_{(cone)} = \pi \: r \: l}\\ \\ \bigstar \: \bf{TSA_{(cone)} = \pi \: r \: (l + r)}\\ \\ \bigstar \: \bf{Volume_{(sphere)} = \dfrac{4}{3}\pi {r}^{3} }\\ \\ \bigstar \: \bf{Volume_{(cube)} = {(side)}^{3} }\\ \\ \bigstar \: \bf{CSA_{(cube)} = 4 {(side)}^{2} }\\ \\ \bigstar \: \bf{TSA_{(cube)} = 6 {(side)}^{2} }\\ \\ \bigstar \: \bf{Volume_{(cuboid)} = lbh}\\ \\ \bigstar \: \bf{CSA_{(cuboid)} = 2(l + b)h}\\ \\ \bigstar \: \bf{TSA_{(cuboid)} = 2(lb +bh+hl )}\\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

6 0

2 years ago

If a man is wallpapering a room 9ft by 9ft by 9ft high. How many square feet of paper will he need if there are 93ft^2 of openin

nexus9112 [7]

Assume that only the four 9 ft by 9 ft walls are to be papered. Each wall will require (9 ft)^2 sq ft of paper, or 81 sq ft of paper. Multiply that by 4 (since there are four walls): 324 sq ft. Now subtract 93 sq ft from 324 sq ft to obtain the answer to this problem.

8 0

3 years ago