Hello, we need to see it as a difference of two squares as we know that for all a and b real numbers
![a^2-b^2=(a-b)(a+b)](https://tex.z-dn.net/?f=a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29)
So, here
![9x^2-4=(3x)^2-2^2=(3x-2)(3x+2)](https://tex.z-dn.net/?f=9x%5E2-4%3D%283x%29%5E2-2%5E2%3D%283x-2%29%283x%2B2%29)
Voila !
Thank you
Answer:
![x\geq 6\text{ or } x](https://tex.z-dn.net/?f=x%5Cgeq%206%5Ctext%7B%20or%20%7D%20x%3C-3)
Step-by-step explanation:
We have the compound inequality:
![2(x-1)\geq10\text{ or } 3-4x>15](https://tex.z-dn.net/?f=2%28x-1%29%5Cgeq10%5Ctext%7B%20or%20%7D%203-4x%3E15)
Let's solve each of them individually first:
We have:
![2(x-1)\geq10](https://tex.z-dn.net/?f=2%28x-1%29%5Cgeq10)
Divide both sides by 2:
![x-1\geq5](https://tex.z-dn.net/?f=x-1%5Cgeq5)
Add 1 to both sides:
![x\geq6](https://tex.z-dn.net/?f=x%5Cgeq6)
We have:
![3-4x>15](https://tex.z-dn.net/?f=3-4x%3E15)
Subtract from both sides:
![-4x>12](https://tex.z-dn.net/?f=-4x%3E12)
Divide both sides by -4:
![x](https://tex.z-dn.net/?f=x%3C-3)
Hence, our solution set is:
![x\geq 6\text{ or } x](https://tex.z-dn.net/?f=x%5Cgeq%206%5Ctext%7B%20or%20%7D%20x%3C-3)
2/3+(-1/3)
2/3-1/3
1/3
Your answer is 1/3
37.5 % of 800 is 300 because of division