Select the correct answer.

Plz help me with this

Makovka662 [10]

Answer:

117° I believe.

Step-by-step explanation:

It would make sense. As it would equal the same as the other side

7 0

3 years ago

Read 2 more answers

An old house in Pomona, CA is inhabited by a variety of ghosts. Ghost appearances occur in the house according to a Poisson proc

shutvik [7]

Answer:

The probability is 0.503

Step-by-step explanation:

If the ghost appearances occur in the house according to a Poisson process with mean m, the time between appearances follows a exponential distribution with mean 1/m. so, the probability that the next ghost appearance happens before x hours is equal to:

$P(X\leq x)=1-e^{-xm}$

Then, replacing m by 1.4 ghosts per hour we get:

$P(X\leq x)=1-e^{-1.4x}$

Additionally, The exponential distribution have a memoryless property, so if it is now 1:00 p.m. and we want the probability that ghost appear before 1:30 p.m., we need to find the difference in hours from 1:00 p.m and 1:30 p.m. no matter that the last ghost appearance was at 12:35 p.m.

Therefore, there are 0.5 hours between 1:00 p.m. and 1:30 p.m, so the probability that the 7th ghost will appear before 1:30 p.m is calculated as:

$P(x\leq 0.5)=1-e^{-1.4*0.5} =0.503$

8 0

3 years ago

The weights of soy patties sold by a diner are normally distributed. A random sample of 25 patties yields a mean weight of 4.2 o

just olya [345]

Answer:

$t=\frac{4.2-4}{\frac{0.5}{\sqrt{25}}}=2$

The degrees of freedom are given by:

$df =n-1=25-1=24$

And the p value would be given by:

$p_v = P(t_{24}>2) =0.0285$

And since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case is significantly hiher than 4. And the claim for this case is not appropiate

Step-by-step explanation:

Data provided

$\bar X=4.2$ represent the sample mean for the weigths

$s=0.5$ represent the sample standard deviation

$n=25$ sample size

$\mu_o =4$ represent the value that we want to analyze

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We want to conduct a hypothesis in order to check if the true mean weigth is less than 4 or not, the system of hypothesis would be:

Null hypothesis: $\mu \leq 4$

Alternative hypothesis: $\mu > 4$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{4.2-4}{\frac{0.5}{\sqrt{25}}}=2$

The degrees of freedom are given by:

$df =n-1=25-1=24$

And the p value would be given by:

$p_v = P(t_{24}>2) =0.0285$

And since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case is significantly hiher than 4. And the claim for this case is not appropiate

5 0

3 years ago

Let P be a point not on the line L that passes through the points Q and R. The distance d from the point P to the line L is d =

Goshia [24]

Answer:

Distance from point (0,1,1) to the given line is zero.

Step-by-step explanation:

Given parametric equations of line,

x=2t, y=5-2t, z=1+t

To find distance from (0,1,1), we have to eliminate t from above equations so that,

$y=5-2t=5-x\implies x+y=5=4+1=4+z-t=4+z-\frac{1}{2}x$