Answer:
Explanation: obtain and use energy, make new cells, exchange materials, eliminate wastes
I will use this conversion:
1m = 1000 mm => 1 = 1m / 1000mm
1 m = 100 cm=> 1 = 1m / 100cm
1m = 10 dm=> 1 = 1m / 10 dm
So,
B) 3.8 * 10^7 cm^3 = 3.8 * 10^7 cm^3 * [1m / 100cm]^3 = 38 m^3
C) 3.8 * 10^5 dm^3 * [1m / 10 dm]^3 = 380 m^3
D) 3.8 * 10^8 mm^3 * [1m / 1000 mm]^3 = 0.38 m^3
Now you can compare the four volumes and conclude which is the largest.
Answer: option C) 3.8 * 10^5 dm^3
Answer:
Iron + copper(II) sulphate → iron sulphate + copper
Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
copper + silver nitrate → copper nitrate + silver
Cu (s) + 2AgNO3 (aq) → Cu(NO3)2 (aq) + 2Ag (s)
The type of bond between two elements can be predicted by measuring the electronegativity difference between the two atoms. Based on this difference the type of bonds are classified as,
E.N difference between 0.0 to 0.3 = Non Polar bond
E.N difference between 0.4 to 1.0 = Moderate Polar Covalent Bond
E.N difference between 1.1 to 2.0 = Very Polar Covalent Bond
E.N difference greater than 2.0 = Ionic Bond
So,
(E.N of N) 3.04 - (E.N of C) 2.55 = 0.49
As the difference is between 0.4-1.0, So, the bond between C and N is Moderate Polar Covalent Bond (or Polar Covalent Bond).
Answer:
See Explanation
Explanation:
Let us find the number of moles of each element
For iron = 2.24g/56 = 0.04 moles
For oxygen = 0.96 g/16 = 0.06 moles
Then we divide by the lowest ratio;
0.04/0.04 and 0.06/0.04
1 and 2
We Thus obtain 1 : 1.5
Multiplying through by 2 we have; 2 : 3
The formula of the oxide formed is Fe2O3
The balanced equation is;
4Fe + 3O2 ------> 2Fe2O3
