The answer to this question is 6.25ml
To answer this question, you need to calculate the azithromycin drug doses for this patient. The calculation would be: 25kg * 10mg/kg/d= 250mg/d
Then multiply the doses with the available drug. It would be:
250 mg/d / (200mg/5ml)= 6.25ml/d
One example of a predator prey relationship would be a a shark and a fish. The shark is the predator and the fish is the prey. The predator hunts for the prey.
Answer:
0.653
Explanation:
1)
M1V1 = M2V2
M1 = 5.04 M
V1 = 229 mL ( you take only this volume)
V2 = 921 mL
5.04*229 = M2 * 921
M2 = (5.04*229)/921 Molarity
2)
M1V1 = M2V2
M1 = (5.04*229)/921
V1 = 100 mL
V2= 192 mL
(5.04*229)/921 *100 = M2 * 192
M2 = [(5.04*229)/921 *100]/192 = 0.653 final molarity
Energy in the nucleus of an atom of uranium: Nuclear energy
Energy of a moving object: Kinetic Energy
Energy stored in chemical bonds: Potential Energy
Energy emitted from light bulb: Radiant Energy
Energy in a battery: Stored Energy
Energy in our food: Chemical Energy
Energy emitted from a radio: Electromagnetic Energy
Energy affected by mass and speed: Kinetic Energy
Energy affected by position and condition: Potential Energy
Energy from our star that some homes use for electricity: Radiant Energy
I hope this was found helpful!
I was happy to assist you with your Homework :)
Answer:
a) ionic b) polar covalent c) nonpolar covalent
Explanation:
To determine if a bond is covalent or ionic without knowing the electronegativities is to see if it is a metal-nonmetal bond or a nonmetal-nonmetal bond. Metal-nonmetal bonds are ALWAYS ionic, and nonmetal-nonmetal bonds are ALWAYS covalent. A is the metal-nonmetal bond and thus ionic. B & C are both nonmetal-nonmetal bonds and thus covalent.
Polarity:
To determine if a covalent bond is polar or not, we need to see how far apart the elements are away from one another. The further away the elements are from one another the more polar the bond. Nonmetal elements bonded to themselves are ALWAYS nonpolar see compound C. For B, the elements are far apart and are still covalent, so these bonds are polar.
