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weqwewe [10]
3 years ago
11

The volume of the nucleus of a carbon atom is about 9.9 10⁻³⁹. the molar mass of carbon is 12.00 g mol⁻¹. what is the density of

the carbon nucleus?
Chemistry
1 answer:
IrinaVladis [17]3 years ago
3 0

Density is defined as the ratio of mass to the volume.

Density = \frac{Mass}{Volume}        (1)

Since, molar mass of carbon is given i.e. 12.00 g mol^{-1}, determine the mass of carbon, we get

1 amu = 1 g/mol

1 amu = 1.66\times 10^{-24} g

Mass of carbon = 12.00 \times 1.66\times 10^{-24}

= 19.92\times 10^{-24} g

=  1.992\times 10^{-23} g

Now, put the value of mass and volume in formula (1)

Density of carbon nucleus =  \frac{1.992\times 10^{-23} g}{9.9 \times 10^{-39} mL}  

= 0.201 \times 10^{16} g/mL

= 2.01 \times 10^{15} g/mL

Hence, density of carbon nucleus = 2.01 \times 10^{15} g/mL

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Answer:

A

Explanation:

The answer A is the best answer because it contains the most general characteristic of a chemical change.

5 0
3 years ago
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A given mass of air has a volume of 8.00 L at 60.0°C. At constant pressure, the temperature is increased to 80.0°C. Calculate th
AleksandrR [38]

Answer:

D. 6.00 L

Explanation:

What we have here is an example of Boyle's Law. The equation here is P₁ · V₁ = P₂ · V₂. We know all of the values except for V₂.

60(8) = 80V

<em>Multiply 60 by 8 to get 480.</em>

480 = 80V

<em>Divide both sides by 80.</em>

480/80 = V

6 = V

The final volume for the gas is 6.00 L.

5 0
3 years ago
what is the molar mass of a gaseous flouride of sulfur containing 70.4% F and having a density of approximately 4.5g/L at 20 deg
zlopas [31]

Answer:

The molar mass is 180.2 g/mol

Explanation:

<u>Step 1:</u> Data given

% of F = 70.4 %

Density = 4.5 g/L

Temperature = 20 °C

Pressure = 1 atm

<u>Step 2:</u> Calculate the number of moles

PV = nRT

 ⇒ with P = the pressure = 1.00 atm

⇒ with V = the volume = Assume this is 1L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature : 20°C = 293 Kelvin

1 atm*1L= n(0.08206 L-atm/mol-K)*(293 K)

n = 0.04159 moles

<u>Step 3</u>: Calculate molar mass

Molar mass = Mass / moles

4.5 grams / 0.04159 moles = 108.2 g/mol

<u>Step 4:</u> Calculate moles of F

Moles = Mass / molar mass

Moles F = 70.4 g / 19 g/mol

Moles F =  3.70 moles

Moles S = 29.6g / 32.07 g/mol

Moles S = 0.923 moles S

<u>Step 5:</u> Divide by the smallest amount of moles

F = 3.70 / 0.923 = 4

S = 0.923 / 0.923 = 1

The empirical formula is SF4

The molar mass of SF4 = 32.07 + 4*19 = 108.07 g/mol

This means the empirical formula is the same as the molecular formula SF4

The molar mass is 180.2 g/mol

4 0
3 years ago
Who discovered atomic structure​
Yuliya22 [10]
John Dalton

Although the concept of the atom dates back to the ideas of Democritus, the English meteorologist and chemist John Dalton formulated the first modern description of it as the fundamental building block of chemical structures.
4 0
3 years ago
The half life for the decay of carbon-14 is 5.73 x 10 years. Suppose the activity due to the radioactive decay of the carbon-14
Elena-2011 [213]

Answer:

Age of the atifact is 4.2\times 10^{2} years

Explanation:

  • For first -order radioactive decay- A_{t}=A_{0}(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}
  • A_{t} represents activity of radioactive nuclide after t time, A_{0} represents initial activity of radioactive nuclide and t_{\frac{1}{2}} represents half-life
  • Here, A_{t}=19Bq, A_{0}=20Bq and t_{\frac{1}{2}}=5.73\times 10^{3}years

Plug-in all the given values in the above equation-

19=20\times (\frac{1}{2})^{\frac{t}{5.73\times 10^{3}}}

or, t=4.2\times 10^{2}

So, age of the atifact is 4.2\times 10^{2} years

6 0
3 years ago
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