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3 years ago

Please give me the answer

Mathematics

1 answer:

EleoNora [17]3 years ago

4 0

Answer:

50 degrees

Step-by-step explanation:

Since the two sides have the same length of 7 cm, it is an isosceles triangle so x = (180-80) / 2 = 50

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LekaFEV [45]

B it is going to give you the answer

4 0

3 years ago

Equation 1:Ax+By=C Equation 2:Dx+Ey=F A, B, C, D, E, and F are non-zero real numbers. Which of the following could replace equat

Gnesinka [82]

A, B and E.

Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D.

7 0

3 years ago

What is the value of x in the equation 25x^2 = 16?

Lera25 [3.4K]

25x^2 = 16

divide each side by 25

x^2 = 16/25

take the square root of each side

sqrt (x^2) = +- sqrt(16/25)

x = +- sqrt(16)/sqrt(25)

x = +- 4/5

x = 4/5, - 4/5

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B12%7D%7Bx%7D%20%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B6%7D%7B%20%7Bx%7D%5E%

soldi70 [24.7K]

Answer:

x = 1/2

y = 24

Step-by-step explanation:

y = 12 / x

y = 6 / x²

12 / x = 6 / x²

x² / x = 6 / 12

x = 1 / 2

y = 12 / x

y = 12 / (1/2)

y = 24

4 0

3 years ago

Galileo wanted to release a wooden ball and an iron ball from a height of 100 meters and measure the duration of their fall. He

kotegsom [21]

Answer:

He would need to climb 480.97 m

Explanation:

The ground, the plane to climb and the altitude (100 m) all form a right-angled triangle

Therefore, we can apply the special trig functions.

These functions are as follows:

sin(θ) = $\frac{opposite}{hypotenuse}$

cos(θ) = $\frac{adjacent}{hypotenuse}$

tan(θ) = $\frac{opposite}{adjacent}$

From the diagram, we have:

θ = 12°

The distance that he needs to climb is the hypotenuse

The altitude = 100 m is the opposite

Therefore, we can use the sin function as follows:

sin(12°) = $\frac{100}{hypotenuse}$

hypotenuse = $\frac{100}{sin(12)}$

hypotenuse = 480.97 meters to the nearest hundredth

Therefore, he would need to climb 480.97 meters

Hope this helps :)

5 0

3 years ago

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